The time it would take for the bacteria to reach 1119 is 5.83 hours
<h3>Calculations and Parameters:</h3>
Given the function:
- Initial amount= 50
- amount after 3 hours= 80
To find the exponential growth;
80 = 
If there is a constant growth, then to get to 1119:
1119= 
3.8 = 0.533*t
t= 5.83 hours
Therefore, it would take 5.83 hours for the bacteria to increase to 1119.
Read more about exponential growth here:
brainly.com/question/2456547
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Answer:
12,145
Step-by-step explanation:
If 347 cans is the max PER week, and they have 35 weeks, then all we need to do is multiply 347 times 35.
347*35 = 12,145
The max amount of cans they can collect in 35 weeks is 12,145 cans.
Simplify the following:
(6^5/7^3)^2
7^3 = 7×7^2:
(6^5/(7×7^2))^2
7^2 = 49:
(6^5/(7×49))^2
7×49 = 343:
(6^5/343)^2
6^5 = 6×6^4 = 6 (6^2)^2:
((6 (6^2)^2)/343)^2
6^2 = 36:
((6×36^2)/343)^2
| | 3 | 6
× | | 3 | 6
| 2 | 1 | 6
1 | 0 | 8 | 0
1 | 2 | 9 | 6:
((6×1296)/343)^2
6×1296 = 7776:
(7776/343)^2
(7776/343)^2 = 7776^2/343^2:
7776^2/343^2
| | | | 7 | 7 | 7 | 6
× | | | | 7 | 7 | 7 | 6
| | | 4 | 6 | 6 | 5 | 6
| | 5 | 4 | 4 | 3 | 2 | 0
| 5 | 4 | 4 | 3 | 2 | 0 | 0
5 | 4 | 4 | 3 | 2 | 0 | 0 | 0
6 | 0 | 4 | 6 | 6 | 1 | 7 | 6:
60466176/343^2
| | | 3 | 4 | 3
× | | | 3 | 4 | 3
| | 1 | 0 | 2 | 9
| 1 | 3 | 7 | 2 | 0
1 | 0 | 2 | 9 | 0 | 0
1 | 1 | 7 | 6 | 4 | 9:
Answer: 60466176/117649
For this case we have the following equation:
h = -16t ^ (2) + 30t + 6
We substitute the value of h = 10 in the equation:
10 = -16t ^ (2) + 30t + 6
Rewriting we have:
0 = -16t ^ (2) + 30t + 6-10
0 = - 16t ^ (2) + 30t - 4
We look for the roots of the polynomial:
t1 = 0.144463904
t2 = 1.730536096
"the ball passes its maximum height, it comes down and then goes into the hoop". Therefore, the correct root is:
t = 1.730536096
Answer:
It goes into the hoop after:
t = 1.73 seconds
Not too sure but I think it’s A. Linear Trinomial
Hope it helps!
