Annual sales for a company are $155,000 and increases at a rate if 8% per year for 9 years
2 answers:
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Answer: C. 8 hundred thousand
Step-by-step explanation:
Assuming the given profit function is:
Then we differentiate:
And we set the derivative equal to 0 and solve the resulting equation in order to get the critical points:
Divide by -3 the equation:
Factor:
Set each factor equal to zero and solve:
Then we check which is the maximum by using the first derivative test.
Into the derivative, let’s plug x=0 which is a value in the interval before the critical point x=2:
The derivative is negative, so the profit function is decreasing before x=2
Into the derivative, let’s plug x=3 which is a value in the interval after the critical point x=2 and before the critical point x=8:
The derivative is positive, so the profit function is increasing between x=2 and x=8
Notice then at x=2 we have a local minimum since the function changed from decreasing to increasing there.
Into the derivative, let’s now plug x=10 which is a value in the interval after the critical point x=8:
The derivative is negative, so the profit function is decreasing after x=8.
Therefore, at x=8 we have a local maximum because the function changed from increasing to decreasing there.
So, the solution is x=8, meaning 8 hundred thousand tires must be sold to maximize profit. That is option C.
Answer:
Side Q'S' lies on a line with a slope of -1.
The distance from Q' to the origin is twice the distance from Q to the origin.
Step-by-step explanation:
The explanations are as follows
As we can see from the attached figure that the ΔQ'R'S' is dilated i.e transformation is made or change in size
Now
Based on
(x,y) = (2x,2y)
The intercepts are as follows
For S
(-1,1) = (-2,2)
For Q
(-3,3) = (-6,6)
For S
(2,4) = (4,8)
Based on this we can say that the three above options are correct
