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ahrayia [7]
3 years ago
9

Please help!!thank you !!​

Mathematics
1 answer:
Sever21 [200]3 years ago
6 0

Remember, triangles add up to 180 degrees.

180-(96+67)=17.

A is 17 degrees.

Hope this helped!

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How to do this question
Tema [17]

Answer:

f(8) = \underline{5}

Step-by-step explanation:

We can see it on the given table of values.

6 0
3 years ago
An angle whose measure is _____ is rotated more than halfway around a circle
zaharov [31]

The correct answer is 60⁰.

Step-by-step explanation:

  • An angle whose measure is 60⁰ is rotated more than halfway around a circle.
  • Since, we have to find the measure of angle.  
  • As we already know that the angle of rotation about a circle is 360° therefore we have to find more than halfway of this angle.
  • Considering that an angle is rotated more than halfway around a circle be \frac{1}{6}
  • Multiplying \frac{1}{6} with 360⁰
  • Therefore, it can show as \frac{1}{6}×360⁰
  • Which gives the result to be 60⁰
  • Hence, when an angle is measured 60⁰, it is rotating more than halfway around a circle.
  • A single rotation around a circle is equal to 360 degrees.
  • The measurement of an angle shows the magnitude and direction of the rotation of the angle from its initial position to the final position.
  • If the rotation is in a counterclockwise direction, it has an angle with positive measure. If the rotation is clockwise, it has an angle which gives negative measure.

4 0
3 years ago
Read 2 more answers
Connor wants to attend the town carnival. The price of admission to the
Vesna [10]

Answer:

14 rides

Step-by-step explanation:

16 = 0.79x + 4.5

11.5 = 0.79x

x = 14.55 or 14

rounding down because it can't go over $16.

0.79(14) + 4.5 = $15.56

7 0
3 years ago
An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

7 0
3 years ago
The question is in a screenshot please help ty
ICE Princess25 [194]
Your answer will most likely be D. h > 42 and h must be a positive number. Reasoning: H has to be greater than 42 to ride the ride, and it cannot be a negative number because H has to be greater than 42 and if you make it negative, it will be less than 42
5 0
4 years ago
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