The missing numbers would be 12-6
A * b = 30
a - b = 1
a + b = 11
take ur last 2 equations, and add them
a - b = 1
a + b = 11
--------------add
2a = 12
a = 12/2
a = 6
now its just a matter of subbing
a + b = 11
6 + b = 11
b = 11 - 6
b = 5
so a = 6 and b = 5...whose product is 30, whose difference is 1, and whose sum is 11.
Answer:
3424
Step-by-step explanation:
42422434344
For this problem, I'd use cross-multiplication.
9/12 = x/8.
When cross multiplying, multiply 12*x and 9*8. This leads to a new equation:
12x = 72.
Then you solve as an algebra problem.
*Divide 12 on both sides*
x = 6.
Answer: 4 quotes
3.5 quotes
Step-by-step explanation:
Khan