Answer:
We start with the equation:
A: 3*(x + 2) = 18
And we want to construct equation B:
B: X + 2 = 18
where I suppose that X is different than x.
Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:
3*(x + 2) = X + 2
Now we can isolate the variable x.
(x + 2) = (X + 2)/3
x = (X + 2)/3 - 2
Then we need to replace x by (X + 2)/3 - 2 in equation A, and we will get equation B.
Let's do it:
A: 3*(x + 2) = 18
Now we can replace x by = (X + 2)/3 - 2
3*( (X + 2)/3 - 2 + 2) = 18
3*( (X + 2)/3 ) = 18
3*(X + 2)/3 = 18
(X + 2) = 18
Which is equation B.
Answer:
Add
−
1
and
2
.
2
,
2
s
+
1
Step-by-step explanation:
It will be written like <span>log (base b) N = x . </span>
It would be the first one because it’s going up by a constant rate
Answer:
27x^3 - 54x^2 + 36x - 8
Step-by-step explanation:
(3x - 2)^3
= (3x - 2) (3x - 2) (3x - 2)
= 27x^3 - 54x^2 + 36x - 8
Hope this helps :)
Let me know if there are any mistakes!!
