Answer:
The percent increase between getting a high school scholarship and bachelor's degree is <u>59.14%</u>.
Step-by-step explanation:
Given:
High school scholarship is $421.
Bachelor's degree is $670.
Now, to find the percent increase between a high school scholarship and bachelor's degree.
So, we get the amount of increase between a high school scholarship and bachelor's degree.

<em>Thus, the amount of increase = $249</em>.
Now, to get the percent increase between a high school scholarship and bachelor's degree:



Therefore, the percent increase between getting a high school scholarship and bachelor's degree is 59.14%.
Answer:
3.785, but rounded to the nearest tenth is 3.8
Step-by-step explanation:
Hope this helps!
Answer:
Step-by-step explanation:
-31
1. S= 5/6 or 0.833333
2. 0
When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.