Missing factors to find the given estimated product of 6,397×349

Which function rule describes the number of centimeters y as a function of a number of millimeters x?

ira [324]

Y= 10x
y: number of cm
x: number of mm

7 0

3 years ago

Joe spent 15/22 of his pocket money in a story book which costs $75. How many pocket money did he have at first?

ehidna [41]

Answer:

$51.1

Step-by-step explanation:

If Joe spent 15/22 of his pocket money in a story book which costs $75, he had $51.1 at first.

15/22 of 75 = 51.1363636364 or 51.1

6 0

3 years ago

Read 2 more answers

Someone help me please?

gavmur [86]

The answer would be Acute angles

7 0

3 years ago

The annual expenditure of the US federal government is approximately 4 44 trillion dollars. If a one dollar bill is 0 . 0 0 0 1

kaheart [24]

Answer:

<em>A stack of 4 trillion one dollar bills will be $4\times 10^8$ meters.</em>

Step-by-step explanation:

The annual expenditure of the US federal government is approximately 4 trillion dollars.

We know, 1 trillion dollars = 10¹² dollars.

So, 4 trillion dollars $=(4\times 10^1^2)$ dollars.

Each one dollar bill is 0.0001 meters thick.

So, the total height of the stack of 4 trillion one dollar bills will be.....

$[0.0001\times(4\times 10^1^2)]meters\\ \\ =[10^-^4\times(4\times 10^1^2)]meters\\ \\ =(4\times 10^8) meters$

6 0

3 years ago

Let X represent the amount of gasoline (gallons) purchased by a randomly selected customer at a gas station. Suppose that the me

Alexus [3.1K]

Answer:

a) 18.94% probability that the sample mean amount purchased is at least 12 gallons

b) 81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c) The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we can apply the theorem, with mean $\mu$ and standard deviation $s = \sqrt{n}*\sigma$

In this problem, we have that:

$\mu = 11.5, \sigma = 4$

a. In a sample of 50 randomly selected customers, what is the approximate probability that the sample mean amount purchased is at least 12 gallons?

Here we have $n = 50, s = \frac{4}{\sqrt{50}} = 0.5657$

This probability is 1 subtracted by the pvalue of Z when X = 12.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{12 - 11.5}{0.5657}$

$Z = 0.88$

$Z = 0.88$ has a pvalue of 0.8106.

1 - 0.8106 = 0.1894

18.94% probability that the sample mean amount purchased is at least 12 gallons

b. In a sample of 50 randomly selected customers, what is the approximate probability that the total amount of gasoline purchased is at most 600 gallons.

For sums, so $mu = 50*11.5 = 575, s = \sqrt{50}*4 = 28.28$