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xeze [42]
4 years ago
6

Students in an art class make square tiles that are 5 inches long.They plan to make a row of tiles that is 4feet 2 inches long.

How many tiles will the students need to make ?
Mathematics
2 answers:
Andreas93 [3]4 years ago
8 0
4ft 2in is equivalent to 50in. By dividing the length of the entire row of tiles by the length of each individual tile, you will get the answer of 10.

Equation: ((4x12)+4)/5
g100num [7]4 years ago
5 0
4 feet 2 inches = 50 inches
50 / 5 = 10 square tiles
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answer A

Step-by-step explanation:

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so the correct answer is A.

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The local movie theater offers a 15 percent discount to senior citizens. If the regular movie price is $8.00, how much is it for
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The answer is $6.80.

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prove the following identity: sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x please provide a proof in some shape form or fash
wolverine [178]

Answer:

Step-by-step explanation:

Hello,

<u><em>Is this equality true ?</em></u>

sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x

<u>1. let 's estimate the left part of the equation</u>

sec(x)csc(x)(tan(x) + cot(x)) =\dfrac{1}{cos(x)sin(x)}*(\dfrac{sin(x)}{cos(x)}+\dfrac{cos(x)}{sin(x)})\\\\=\dfrac{1}{cos(x)sin(x)}*(\dfrac{sin^2(x)+cos^2(x)}{sin(x)cos(x)})\\\\=\dfrac{1}{cos(x)sin(x)}*(\dfrac{1}{sin(x)cos(x)})\\\\\\=\dfrac{1}{cos^2(x)sin^2(x)}

<u>1. let 's estimate the right part of the equation</u>

<u />2+tan^2(x) + cot^2(x)=2+\dfrac{sin^2(x)}{cos^2(x)}+\dfrac{cos^2(x)}{sin^2(x)}\\\\=\dfrac{2cos^2(x)sin^2(x)+cos^4(x)+sin^4(x)}{cos^2(x)sin^2(x)}\\\\=\dfrac{(cos^2(x)+sin^2(x))^2}{cos^2(x)sin^2(x)}\\\\=\dfrac{1^2}{cos^2(x)sin^2(x)}\\\\=\dfrac{1}{cos^2(x)sin^2(x)}<u />

This is the same expression

So

sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x

hope this helps

7 0
3 years ago
An urn contains 4 black and 5 white balls. A ball is drawn at random and then replaced, and then a second ball is drawn. Find th
valkas [14]

Answer:

Probability = 0.2470

Step-by-step explanation:

Given

Black = 4

White = 5

Total = 9 i.e. 5 + 4

Required

Determine P(Black\ and\ White)

In probability;

P(A\ and\ B) = P(A) * P(B)

So:

P(Black\ and\ White) = P(Black) * P(White)

<em>i.e. multiply the probability of selecting black by that of selecting white</em>

P(Black\ and\ White) = \frac{n(Black)}{Total} * \frac{n(White)}{Total}

P(Black\ and\ White) = \frac{4}{9} * \frac{5}{9}

Probability = \frac{20}{81}

Probability = 0.2470

3 0
3 years ago
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