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LenaWriter [7]
3 years ago
13

A random sample of 8888 eighth grade​ students' scores on a national mathematics assessment test has a mean score of 278278. Thi

s test result prompts a state school administrator to declare that the mean score for the​ state's eighth graders on this exam is more than 270270. Assume that the population standard deviation is 3838. At alphaαequals=0.150.15​, is there enough evidence to support the​ administrator's claim? Complete parts​ (a) through
Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

Step-by-step explanation:

Given that sample size n = 88, for eight grade students

scores on a national mathematics assessment test has a mean score of 278. This test result prompts a state school administrator to declare that

x bar >270

H_0: xbar = 270\\H_a: x bar >270

(One tailed test at 15% sign level)

Since sigma, population sd is known and sample size is large we use z test

Std error = \frac{\sigma}{\sqrt{n} } =4.051

Mean difference 278-270=8

Z statistic = \frac{8}{4.051} =1.975

p value = 0.024

Since p <alpha, the administrator's declaration is correct.

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2 years ago
If 6:2=8:x, then<br> a. 6x=16<br> b. 6x=10<br> c.2x=48<br> d. 2x=14
otez555 [7]

Answer:

a)6x = 16

Step-by-step explanation:

<h2><u>Finding the value</u></h2>

the ratio can be solved by <u>cross multiplication :</u>

6       :          2

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6*x = 8*2

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2 years ago
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Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.
alexira [117]

Answer:

Option B

Step-by-step explanation:

Given quadratic equation is,

12a² + 9a + 7 = 0

By comparing this equation with standard quadratic equation,

hx² + kx + c = 0

h = 12, k = 9 and c = 7

By using quadratic formula,

a = \frac{-k\pm\sqrt{k^2-4hc}}{2h}

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  = \frac{-9\pm\sqrt{81-336}}{2(12)}

  = \frac{-9\pm\sqrt{-255}}{24}

  = \frac{-9\pm i\sqrt{255}}{24}

a = \frac{-9+ i\sqrt{255}}{24},\frac{-9- i\sqrt{255}}{24}

Therefore, Option B will be the correct option.

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