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Scilla [17]
3 years ago
13

Mary reduced the size of a painting to a width of 3.3 in. What is the new height if it was originally 32.5 in tall and 42.9 in w

ide?
Mathematics
1 answer:
posledela3 years ago
6 0
The ratio of the height and width remain constant as you change it's size.
So..
A = Old width
B = Old height
C = New width
D = New height

A/B = C/D

Plug in the values we have

42.9 / 32.5  = 3.3 / D

Multiple both sides by D
D * 42.9 / 32.5 = 3.3

Multiple both sides by 32.5

D * 42.9 = 3.3 * 32.5

Now divide both sides by 42.9

D = 3.3 * 32.5 / 42.9

Now simply do the multiplication and division using the available numbers.
D = 2.5

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How to round 106.327 to nearest hundredths explain
scoray [572]

Answer:

106.33

Step-by-step explanation:

after decimal you have .3 tenths 2 hundredths 7 thousandths

to round to the nearest hundredths look at thousandths 7 becasuse is greater then 5 then you round up

106.327 is rounded to 106.33

8 0
3 years ago
Read 2 more answers
I need help on number 4. Please help me!
Andreas93 [3]
S= R- 1/3R

The first problem s=18 r-= 6
This is how it works

Use S-= R-1/3R
12= 18-1/3(18)
12= 18-6
12=12

8 0
3 years ago
Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed
vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 11-1 = 10.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have T = 1.812

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{4}{\sqrt{11}} = 1.2060

Now, we multiply T and s

M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 97 + 2.19 = 99.19 = 99.2cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0
3 years ago
NEED HELP ASAP!!! What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15 A stem-and-lea
monitta
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.

Find the median of the data (30.5)

Find the median of the lower half and the median of the upper half.

Subtract these two values.

The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
                            27.5                40.5
40.5-27.5 = 13

The interquartile range is 13.
3 0
3 years ago
Read 2 more answers
A retailer ordered a combination of 50 black and white sweatshirts. Each white sweatshirt cost him $10 and
Brut [27]

The number of white  sweatshirts is 28

Step-by-step explanation:

Let ordered black shirts be represented by b

Let ordered white shirts be represented by w

So total sweatshirts will be represented by the equation

b+w=50

The total cost of the ordered sweatshirts will be represented by

10b + 12 w= $556

For simultaneous equations as;

b+w=50

10b+12w=556

solving the equations using substitution method where b=50-w

10(50-w)+12w=556

500-10w+12w=556

-10w+12w=556-500

2w=56

w=56/2= 28

b=50-w=50-28=24

Number of white  sweatshirts  is 28

Learn More

Simultaneous equation :brainly.com/question/12919422

Keyword : cost

#LearnwithBrainly

4 0
3 years ago
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