Answer:
To remember the order of taxa in biology (Domain, Kingdom, Phylum, Class, Order, Family, Genus, Species, [Variety]): "Dear King Philip Came Over For Good Soup" is often cited as a non-vulgar method for teaching students to memorize the taxonomic classification system.
Answer:
The numerical value of K for the reaction is 2.36*10⁻⁴
Explanation:
A chemical equilibrium is a reaction that is never completed, since it occurs simultaneously in both directions (the reactants form products, and in turn, these form reactants again). In other words, it is a dynamic balance. When the concentrations of each of the substances involved (reactants or products) stabilize, that is, they are spent at the same rate as they are formed, chemical equilibrium is reached.
The equilibrium constant (Kc) is expressed as the ratio between the molar concentrations of reactants and products. Its value in a chemical reaction depends on the temperature, so this must always be specified.
Being:
aA + bB ⇄ cC + dD
then the constant Kc is:
In the case of the reaction:
A₂(g) + 3 B₂(g) ⇒ 2 AB₃(g)
The constant Kc is:
Being:
- [AB₃]=7.6*10⁻⁴
- [A₂]= 0.0055
- [B₂]= 0.763
and replacing, you get:
Kc=2.36*10⁻⁴
<u><em>The numerical value of K for the reaction is 2.36*10⁻⁴</em></u>
The answer to the first one is C. Strong attraction between ions
The answer to the second one is A. High melting points
Hope this helps :)
Answer:
In a controlled experiment, an independent variable (the cause) is systematically manipulated and the dependent variable (the effect) is measured; any extraneous variables are controlled. State what steps you will take to design an experiment to test your hypothesis. Complete the experiment. Make observations. Record what happened during your experiment.
Answer:
453.6 g
Explanation:
The following data were obtained from the question:
Mole of Ag = 4.2 moles
Weight (in grams) of Ag =?
Thus, we can obtain the weight in grams of Ag by doing the following:
Mole of Ag = 4.2 moles
Molar mass of Ag = 108 g/mol
Mass of Ag =.?
Mole = mass /Molar mass
4.2 = mass of Ag /108
Cross multiply
Mass of Ag = 4.2 × 108
Mass of Ag = 453.6 g
Thus, the weight (in grams) of 4.2 moles of Ag is 453.6 g