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3 years ago

How do particles tend to move in solids? Please explain your answer

Chemistry

2 answers:

AlexFokin [52]3 years ago

6 0

They vibrate abour fixed points.

Since particles have charges that attract each other it stays intact.

Musya8 [376]3 years ago

6 0

Answer: Option (d) is the correct answer.

Explanation:

Since, it is known that in solids strong intermolecular forces of attraction exists because of which particles are much closer to each other. Hence, they have definite shape and volume.

Particles of a solid are unable to move from their initial position unless an external force is applied to them. So, when no external force is applied then particles of a solid tend to vibrate at their fixed points.

Hence, we can conclude that particles tend to move in solids as they vibrate about fixed points.

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Which is the smallest number?

My name is Ann [436]

Answer:

What I came up with was D equaling out to be 42

Explanation:

Im assuming you just do the math

A. 3.5 x 104 = 364

B. 2.4 x 103 = 247.2

C. 1.4 x 10^2_2 = 280

D. 4.9 x 10-7 = 42

I hope I helped.

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3 years ago

Which of the following conclusions might a scientist make when fossils of two different species of very similar organisms are fo

nata0808 [166]

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if its multiple, C and D, if not, C

Explanation:

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3 years ago

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The ones with 8 protons

Explanation:

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3 years ago

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

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2 years ago

what is the molecular formula for a compound that is 39.99% carbon, 6.73% hydrogen, and 53.28% oxygen and has a molar mass of 18

4vir4ik [10]

Answer:

IDEK

Explanation:

5 0

3 years ago