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Mashutka [201]
1 year ago
8

Please help answer this question

Chemistry
1 answer:
Nesterboy [21]1 year ago
4 0

Answer:

hahah animals in the world

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They depend on people to water them and make sure they are by a window for sunlight

Explanation:

plants cant do these things by themselves

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Why does the amount of water that flows in a river change during the year?
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7 0
3 years ago
Malonic acid, h2c3h2o4, is a diprotic acid with ka1= 1.5 x 10-3and ka2= 2.0 x 10-6. what is the concentration of the malonate an
Bess [88]

In a 0.15 m solution of malonic acid, the amount of the malonate anion, c3h2o42-, is 1.68*10^{-4} M.

Explanation:

For the first equlibria;

initial concentration of H_{2}C_{3}H_{2}OH=0.15

initial concentration of HC_{3}H_{2}O_{4}^{-} =0

initial concentration of H^{+} =0

Let concentration change of H_{2}C_{3}H_{2}OH=-x

Let concentration change of HC_{3}H_{2}O_{4}^{-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  H_{2}C_{3}H_{2}OH=0.15-x

Let concentration in equilibrium state ofHC_{3}H_{2}O_{4}^{-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{1}=\frac{x*x}{0.15-x}=\frac{1.5*10^{-3}}{1} =\frac{x^{2}}{0.15-x}

x^{2}+0.0015x-0.000225=0

Which is a quadratic equation in x, solving it gives;

x=0.01427

Therefore, HC_{3}H_{2}O_{4}^{-} =x= 0.01427M

Now for the second equlibria;

initial concentration of HC_{3}H_{2}O_{4}^{-}=0.01427

initial concentration of C_{3}H_{2}O_{4}^{2-} =0

initial concentration of H^{+} =0

Let concentration change of HC_{3}H_{2}O_{4}^{-}=-x

Let concentration change of  C_{3}H_{2}O_{4}^{2-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  HC_{3}H_{2}O_{4}^{-}=0.01427-x

Let concentration in equilibrium state ofC_{3}H_{2}O_{4}^{2-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{2}=\frac{x*x}{0.01427-x}=\frac{2.0*10^{-6}}{1} =\frac{x^{2}}{0.01427-x}

2.854*10^{-8}-(2.0*10^{-6})x=x^{2}

Therefore, C_{3}H_{2}O_{4}^{2-} =x= 1.68*10^{-4}M

<h3>What is a malonic acid?</h3>

The chemical formula of malonic acid is CH2(COOH)2. Malonates include the ionized form of malonic acid as well as its esters and salts. For instance, the diethyl ester of malonic acid is called diethyl malonate.

Polyester and polymers both employ malonic acid as a precursor. Both the scent business and the flavoring sector utilize it. It is employed to regulate acidity. Malonic acid contributes to the production of fatty acids in people. Malonic acid has been found in a number of foods outside of the human body, including red beets, corn, scarlet beans, common beets, and cow milks, although its presence has not been defined. The group of organic substances known as dicarboxylic acids and derivatives includes malonic acid, also known as malonate or H2MALO.

To know more about malonic acid, visit:

brainly.com/question/13943912?referrer=searchResults

#SPJ4

4 0
1 year ago
Magnesium metal burns in air to form a mixture of magnesium oxide (MgO, M = 40.31) and magnesium nitride (Mg3N2, M = 100.95). A
dedylja [7]

Answer:

26.95 %

Explanation:

Air contains the highest percentage of oxygen and nitrogen gases. Magnesium then combines with both of the gases:

2 Mg (s) + O_2 (g)\rightarrow 2 MgO (s)

3 Mg (s) + N_2 (g)\rightarrow Mg_3N_2 (s)

Firstly, find the total number of moles of magnesium metal:

n_{Mg} = \frac{1.000 g}{24.305 g/mol} = 0.041144 mol

Let's say that x mol react in the first reaction and y mol react in the second reaction. This means:

x + y = 0.041144 mol

According to stoichiometry, we form:

n_{MgO} = x mol, n_{Mg_3N_2} = \frac{y}{3} mol

Multiplying moles by the molar mass of each substance will yield mass. This means we form a total of:

m_{MgO} = 40.31x g, m_{Mg_3N_2} = \frac{y}{3} 100.95 g =

The total mass is given, so we have our second equation to solve:

40.31x + 33.65y = 1.584

We have two unknowns and two equations, we may then solve:

x + y = 0.041144

40.31x + 33.65y = 1.584

Express y from the first equation:

y = 0.041144 - x

Substitute into the second equation:

40.31x + 33.65(0.04144 - x) = 1.584

40.31x + 1.39446 - 33.65x = 1.584

6.66x = 0.18954

x = 0.028459

y = 0.041144 - x = 0.012685

Moles of nitride formed:

n_{Mg_3N_2} = \frac{y}{3} = 0.0042282 mol

Convert this to mass:

m_{Mg_3N_2} = 0.0042282 mol\cdot 100.95 g/mol = 0.4268 g

Find the percentage:

\omega_{Mg_3N_2} = \frac{0.4268 g}{1.584 g}\cdot 100\% = 26.95 \%

7 0
3 years ago
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