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Feliz [49]
4 years ago
5

The picture represents the process that produces most of the energy used by living organisms on Earth. Which process is represen

ted in the picture?

Chemistry
2 answers:
forsale [732]4 years ago
6 0
Wheres the pic i cant answer without the pic
Andreyy894 years ago
6 0

Answer:

here is the image

Explanation:

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3 years ago
A tank of gas has partial pressures of nitrogen and oxygen equal to 1.61 × 10^4 kPa and 4.34 × 10^3 kPa, respectively. What is t
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Answer:

answer is 2.04*10^4 kPa

Explanation:

Dalton's Law of Partial Pressures.

it is because that when the volume and the temperature of a gaseous mixture are kept constant, the total pressure of the mixture is equal to the sum of the partial pressures of its gaseous components .

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1. The hydrogenation of ethene gas at 298 K shows a decrease in disorder (AS-120.7 J/mol-K) during an exothermic reaction ( Delt
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2 years ago
A sample of cesium carbonate, weighing 3.80 g, requires 1.90 g of hydrogen bromide gas to completely decompose to water, cesium
vladimir1956 [14]

Answer:

Choice A. 0.50 g.

Explanation:

According to the question, the reaction here converts

  • caesium (cesium) carbonate and
  • hydrogen bromide

to

  • cesium bromide,
  • carbon dioxide, and
  • water.

By the Law of Conservation of Mass, matter can neither be created nor destroyed in a chemical reaction. (Shrestha et. al, Introductory & GOB Chemistry, Chemistry Libretexts, 2019.)

In other words, the mass of the reactants, combined, shall be the same as the mass of the products, combined.

What's the mass of the reactants?

\rm \underbrace{\rm 3.80\;g}_{\mathrm{Cs_2CO_3}} + \underbrace{\rm 1.90\; g}_{\mathrm{HBr}} = 5.70\;g.

What's the mass of the products?

Let m(\mathrm{CO_2}) represent the mass of carbon dioxide produced in this reaction.

The mass of the products will be:

\rm \underbrace{\rm 5.20\;g}_{\mathrm{CeBr}\text{ and }\mathrm{H_2O}} + \underbrace{m(\mathrm{CO_2})}_{\mathrm{CO_2}}.

The two masses shall be equal. That is:

\rm 5.20\; g + \mathnormal{m}(\mathrm{CO_2}) = 5.70\;g.

m(\mathrm{CO_2}) = \rm 0.50\;g.

In other words, by the Law of Conservation of Mass, the mass of carbon dioxide produced in this reaction will be \rm 0.50\;g.

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In general, as you move from right to left across a period, the number of valence electrons
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As you move from left to right across a period,the number of valence electrons<span>-increases. </span>
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