Answer:
x=-6 y=7
Step-by-step explanation:
8x+5y=-13; x+y=1
Isolate x and substitute
(-13-5y)/8 +y=1
Isolate y
y=7
substitute y=7
(-13-5*7)/8=-6
Which point could be removed in order to make the relation a function? (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}
stepan [7]
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
<em>Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.</em>
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
<h3>So, we need to remove any one (0, –2) or (0, 8) to make the relation a function.</h3>
If we apply the distributive law to right side of the third choice we get:-
-12x - 9 = -9 - 12x
right side = left side so infinite solutions
Answer:
22 units
Step-by-step explanation:
The perimeter of a polygon is said to be the sum of the length of it's sides.
From the question, we have 5 vertices. This means the polygon is a pentagon. It's given vertices are
A = (−1, 3)
B = (−1, 6)
C = (2, 10)
D = (5, 6)
E = (5, 3)
To find the distance between two points, we use the formula
d = √[(y2 - y1)² + (x2 - x1)²]
Between A and B, we have
d(ab) = √[(6 - 3)² + (-1 --1)²]
d(ab) = √(3²) + 0
d(ab) = √9 = 3
Between B and C, we have
d(bc) = √[(10 - 6)² + (2 --1)²]
d(bc) = √[4² + 3²]
d(bc) = √(16 + 9) = √25 = 5
Between C and D, we have
d(cd) = √[(6 - 10)² + (5 - 2)²]
d(cd) = √[(-4)² + 3²]
d(cd) = √(16 + 9) = √25 = 5
Between D and E, we have
d(de) = √[(3 - 6)² + (5 - 5)²]
d(de) = √(-3)² + 0
d(de) = √9 = 3
Between E and A, we have
d(ea) = √[(3 - 3)² + (5 --1)²]
d(ea) = √[0 + (6)²]
d(ea) = √36 = 6
The perimeter is given as
d(ab) + d(bc) + d(cd) + d(de) + d(ea) =
3 + 5 + 5 + 3 + 6 = 22 units
