Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Answer:
Your answer would be the second option
KQL, IQH
Step-by-step explanation:
Answer:
x=8 y=10
Step-by-step explanation:
Answer:
3/15 is pauls probability simplified to 1/5
7/ 14 is Kim's probability simplified to 1/2
so, the overall probability would be 1/10
You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form
You can use the "cover-up" method here to easily solve for 
. It involves fixing a value of 
to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.
- If
, then 
- If
, then 
- If
, then 
So the integral we want to compute is the same as
and each integral here is trivial. We end up with
which can be condensed as
