All categories

3 years ago

Which expression is equivalent to (3m² + 5m - 2) + (-2m +18)? Someone answer ASAP

Mathematics

2 answers:

Montano1993 [528]3 years ago

4 0

3m^2 +5m-2-2m+18

3m^2 +3m+16

Charra [1.4K]3 years ago

4 0

Answer:

3m² + 3 m + 16

Step-by-step explanation:

( 3 m ² + 5 m - 2 ) + ( - 2m + 18 )

Remove the unnecessary parantheses and rewrite

3 m ² + 5 m - 2 - 2 m + 18

combine like terms

3m² + 5 m - 2 m + 18 - 2

calculate the sum

3m² + 3 m + 16

You might be interested in

Can someone solve Pythagorean theorem

Ad libitum [116K]

Answer:

48 units

b= 48 units

Step-by-step explanation:

pythag is $a^2+b^2=c^2$

we have a and c

so substitute them in

$14^2+b^2=50^2$

now you can solve

$196+b^2=2500$

subtract 196 from both sides

$b^2=2500-196$

subtract

2500 - 196 = 2304

$b^2=2304$

solve for the square root

square root of 2304= 48

therefore b= 48 units

5 0

3 years ago

Rewrite the following in the form log(c).<br> log(10) - log(2)

serg [7]

Answer:

log 5

Step-by-step explanation:

We can rewrite this by using a property of logs

log a - log b = log (a/b)

log(10) - log(2)

log(10/2)

log 5

5 0

3 years ago

The difference of a number divided by 7 and 9 is equal to 2. use the variable C what the unknown

bogdanovich [222]

Given that the number is C.
The number divided by 7 is C/7
Difference means we will subtract 9 from C/7.
Therefore, the equation will be:
C/7 - 9 = 2 (multiply all terms by 7 to get rid of the fraction)
C - 63 = 14
C = 14 + 63 = 77

5 0

3 years ago

równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma

Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

$s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\$

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0

2 years ago

I will marke brainliest. what is If 1=3

pogonyaev

Answer:

Step-by-step explanation:

<u>Count the number of letters</u>

1 = one ⇒ 3 letters
2 = two ⇒ 3 letters
3 = three ⇒ 5 letters
4 = four ⇒ 4 letters
5 = five ⇒ 4 letters
6 = six ⇒ 3 letters

3 0

2 years ago

Read 2 more answers