<em>Question:</em>
<em>Abraham has visited at least 50 countries; he plans to visit five new countries per year (Y) for the next several years. Which inequality and solution shows the amount of years they will take for Abraham to meet his goal.</em>
Answer:


Step-by-step explanation:
Given
------ at least

Required
Represent as an inequality
"at least" means 
So the countries he has visited can be represented as thus;

If
1 year = 5 countries
y years would be 5y countries
So, in y years; he'd have visited

To determine the value of y.
We have that
<em>in the world</em>
<em>Substitute 195 for Countries</em>

<em>Collect Like Terms</em>


<em>Divide through by 5</em>


<em>Reorder</em>

This means that; he'll visit all countries in at most 29 years' time
Answer:
y< -1
Step-by-step explanation:
Answer:
B has a smaller initial population of 500
Step-by-step explanation:
Given
See attachment for complete question
Required
The bacteria with the smaller initial population
The initial population is at x = 0
For bacteria A;
when 
For bacteria B, we have:

Substitute 0 for x



So; when x = 0
and 
Because; 500 < 600
We can conclude that B has a smaller initial population of 500
Answer:
43,000: 4.3×10^4
0.0072: 7.2×10^-3
0.0000901: 9.01×10^-5
Step-by-step explanation:
scientific notation: a×10^b, where should be 0<a<10
Step 1. Count the zeros
Step 2. Look at the number left, and determine whether or not it fits in the range of [a]. If not, we divide or multiply 10 to get it fit
------------------------
43,000: 4.3×10^4 (since 43 does not fit, we divide by 10 to get it fit)
0.0072: 7.2×10^-3 (since 0.72 does not fit, we multiply 10 to get it fit)
0.0000901: 9.01×10^-5 (since 0.901 does not fit, we multiply 10 to get it fit)
Hope this helps!! :)
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