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zhannawk [14.2K]
3 years ago
7

What value of c in the equation cx+4y=12 would give the equation a slope of 8? please help me

Mathematics
1 answer:
Lorico [155]3 years ago
7 0

Answer:

1cy

Step-by-step explanation:

c(8)+4y=12

8c+4y=12

12cy /12cy=12 /12cy

1cy

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Solve for x. 1/15+x=3/10
ValentinkaMS [17]

Answer:

x=7/30

Step-by-step explanation:

3/10-1/15

7 0
3 years ago
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Marco starts with a population of 10 bacteria that doubles every day for a number of days, d. He writes the expression 10(2d) to
riadik2000 [5.3K]

Answer:

Marco- 10 is the starting value of the population. 2 is the growth rate of "double each day" with d as an exponent.

Isabella- 1 is the starting population. 1+0.2=1.2 is the rate at which it grows each day.

Step-by-step explanation:

Marco's equation should be 10(2^{d}) since the bacteria double each day. 10 is the starting value of the population. 2 is the growth rate of "double each day" with d as an exponent. This will double each day because:

Day 1 is 2^{1}=2

Day 2 is 2^{2}=4

Day 3 is 2^{3}=8

Day 4 is 2^{4}=16

You'll notice the value doubles each day.

Isabella has a different equation because her population increases by a percentage. We use the simple interest formula to calculate the bacteria's daily increase or interest.

1(1+0.2)d

1 is the starting population.

1+0.2=1.2 is the rate at which it grows each day.

3 0
4 years ago
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Mark rode his bike 22/8 miles. which mixed number shows the fraction of miles he rode his bike
Vlad1618 [11]

Answer:

Hey there!

There aren't any options, but the correct answer would be 2 6/8, which simplifies to 2 3/4.

Let me know if this helps :)

5 0
4 years ago
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Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)
Fantom [35]

Answer:

Given: \sin(x) = (4/5).

Assuming that 0 < x < 90^{\circ}, \cos(x) = (3/5) while \tan(x) = (4/3).

Step-by-step explanation:

By the Pythagorean identity \sin^{2}(x) + \cos^{2}(x) = 1.

Assuming that 0 < x < 90^{\circ}, 0 < \cos(x) < 1.

Rearrange the Pythagorean identity to find an expression for \cos(x).

\cos^{2}(x) = 1 - \sin^{2}(x).

Given that 0 < \cos(x) < 1:

\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}.

Hence, \tan(x) would be:

\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}.

7 0
2 years ago
10) Determine which of the following are functions. 11) What are the domain and range of the following relation?
Sauron [17]

Answer:

10) The first 2 on the left are functions and the one on the top right is a function, but the bottom right is not.

11) Domain = (2, 8, -1, 0) Range = (5, -2, 4, 5)

3 0
3 years ago
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