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3 years ago

The sum of two numbers is 20. One number is three times as large as the second

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

6 0

Answer:

The two numbers are 5 and 15 :D. The statement I would use is: Let x be the smaller number, and let 3x be the larger.

Step-by-step explanation:

If I helped, please mark brainliest !

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Write a corresponding real world problem to represent 2x-125=400

STatiana [176]

Two times a number less one hundred and twenty-five is equal to four hundred

8 0

3 years ago

If you add Natalie’s age and Fred’s age, the result is 41. If you add Fred’s age to 3 times Natalie’s age, the result is 67. Fin

JulsSmile [24]

Answer:

Natalie is 13 years old, while Fred is 28 years old.

Step-by-step explanation:

Given that if you add Natalie’s age and Fred’s age, the result is 41, and if you add Fred’s age to 3 times Natalie’s age, the result is 67, to find how old Fred and Natalie are, the following calculation must be performed:

N + F = 41

3N + F = 67

(67 - 41) / 2 = N

26/2 = N

13 = N

13 x 3 + F = 67

39 + F = 67

F = 67 - 39

F = 28

28 + 13 = 41

Therefore, Natalie is 13 years old, while Fred is 28 years old.

4 0

2 years ago

Factor each.<br><br><br> Please help!

Naddika [18.5K]

Answer:

1) The factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : $x^2-3x+2=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

$x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0$

So, factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: $x^2+2x-8=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

$x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0$

So, factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

7 0

2 years ago

HELLPPP PLEASE WILL GIVE BRAINLIEST

avanturin [10]

Answer:

Step-by-step explanation:

90-65=25

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3 years ago

-3x-3y=3 and y=5x-17

Vesna [10]

The answer for this question is "y = -5/3 and x = 8/3"

5 0

3 years ago