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mr Goodwill [35]
3 years ago
5

The price of Stock A at 9 A.M. Was ​$12.53. Since​ then, the price has been increasing at the rate of ​$0.12 each hour. At noon

the price of Stock B was ​$13.28. It begins to decrease at the rate of ​$0.09 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?
Mathematics
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

1.8571428 hours

Step-by-step explanation:

Given that :

Price of stock A at 9 am = $12.53

Rate of increase = $0.12 per hour

Price of stock B at noon = $13.28

Rate of Decrease = $0.09 per hour

Let number of hours = x

Price of stock A at noon :12.53 + 0.12(3) = 12.89

12.89 + 0.12x = 13.28 - 0.09x

0.12x + 0.09x = 13.28 - 12.89

0.21x = 0.39

x = 0.39 / 0.21

x = 1.8571428

Hence the prices of the stock will be the at about 1.857 hours

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