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Nataly [62]
3 years ago
10

Solve the system of equations. {y=30x+20 y=10x2−80

Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer:

<em>(x, y) = (-8/3, -60)</em>

Step-by-step explanation:

y = 30x + 20

y = 10 * 2 - 80 → y = 20 - 80

y = 30x + 20

y = -60

30x + 20 = -60

x = -8/3

(x, y) = (-8/3, -60)

Hope this helps! :)

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Ket [755]
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Hey Diddle Diddle, the medians the middle:

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( Answer for your question: Mean is 93)

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( Answer for your question: Mode is 87%)

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( Answer for your question: Range is 54.)

I hope this helps! :)
3 0
3 years ago
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1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help
Gnesinka [82]

\huge \boxed{\mathfrak{Question} \downarrow}

  • Simplify :- 1 + - w² + 9w.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\large \sf1 + - w ^ { 2 } + 9 w

Quadratic polynomial can be factored using the transformation \sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where \sf x_{1} and x_{2} are the solutions of the quadratic equation \sf \: ax^{2}+bx+c=0.

\large \sf-w^{2}+9w+1=0

All equations of the form \sf\:ax^{2}+bx+c=0 can be solved using the quadratic formula: \sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)}  \\

Square 9.

\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)}  \\

Multiply -4 times -1.

\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)}  \\

Add 81 to 4.

\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)}  \\

Multiply 2 times -1.

\large \sf \: w=\frac{-9±\sqrt{85}}{-2}  \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is plus. Add -9 to \sf\sqrt{85}.

\large \sf \: w=\frac{\sqrt{85}-9}{-2}  \\

Divide -9+ \sf\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is minus. Subtract \sf\sqrt{85} from -9.

\large \sf \: w=\frac{-\sqrt{85}-9}{-2}  \\

Divide \sf-9-\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}}  \\

Factor the original expression using \sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \sf\frac{9-\sqrt{85}}{2}for \sf\:x_{1} and \sf\frac{9+\sqrt{85}}{2} for \sf\:x_{2}.

\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}

<h3>NOTE :-</h3>

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

\large \sf \: 1 + -  w {}^{2}  + 9w \\  =\large  \boxed{\bf \: 1 -  {w}^{2}   + 9w}

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

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3 years ago
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WINSTONCH [101]

Answer:

-24

Step-by-step explanation:

4a+8-a

a=-2

4(-2)+8-(-2)

-8+-16

=-24

:)

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3 years ago
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A rectangle has a height of 2x^4 with a width of x^2+8x+15. Express the area of the rectangle.
Amiraneli [1.4K]

Hi there!

We know that the formula for the area of a rectangle is height * width. Thus, we can multiply these two expressions together:

2x^4\cdot (x^2+8x+15)\\

Now, we know through the distributive property that we can distribute the 2x^4\\ to everything in the parenthesis. Once this is done, we get:

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Now, we know through the power rule that when two exponents are multiplied together with the same base, the exponent can be added together (x^a \cdot x^b = x^{a+b}). This then would make our equation:

2x^{4+2}+16x^{4+1}+30x^4\\

Giving us for our final answer:

2x^{6}+16x^{5}+30x^4\\

Hope this helps!

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o-na [289]
2.5 answer answer not sure not sure not sure I can't remember
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