Answer:
26.5 m
Step-by-step explanation:
this is the answer
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
Answer:
Here is your answer
Step-by-step explanation:
B) 2x + 5 = 7
vertical line
C) 2x - y = 6
oblique line
D) 3y + 9 = 0
horizontal line
angleD=(7b+1)angle E=(2b+1)and angle F=(b+8)
Answer:
69 feet
Step-by-step explanation:
we have
where
h(t) is the height of the ball
t is the time in seconds
we know that the given equation is a vertical parabola open downward
The vertex is the maximum
so
the y-coordinate of the vertex represent the maximum height of the ball
Convert the quadratic equation into vertex form
The equation in vertex form is equal to
where
(h,k) is the vertex of the parabola
the vertex is the point (2,69)
therefore
The maximum height is 69 ft
