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3 years ago

A sporting goods store pays $110 for a rubber raft. The percent of markup is 55%. Find the raft’s selling price.

1 answer:

4 0

If you would like to find the raft's selling price, you can calculate this using the following steps:

100% + 55% = 155%
155% of $110 = 155% * 110 = 155/100 * 110 = $170.5

The correct result would be $170.5.

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Answer: y = -2x -2

Step-by-step explanation:

Making y the subject of the formula

Subtract 4 from both sides

⇒ y = -2 ( x - 1 ) - 4

y = -2x + 2 -4

y = -2x -2

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3 years ago

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3 years ago

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3 years ago

Calculating conditional probability

laila [671]

Complete Question

Calculating conditional probability

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom.

Here are the results:

Bride :29

Groom :30

BOTH : 20

Given that a randomly selected guest is a friend of the groom, find the probability they are a friend of the bride.

P (bride | groom)

Answer:

The probability is $P(B|G) = \frac{2}{3}$

Step-by-step explanation:

The sample size is $n = 80$

The friend of the groom are $G = 30$

The friend of the groom are $B = 29$

The friend of both bride and groom are $Z = 20$

The probability that a guest is a friend of the bride is mathematically represented as

$P(B) = \frac{29}{80}$

The probability that a guest is a friend of the groom is mathematically represented as

$P(G) = \frac{30}{80}$

The probability that a guest is both a friend of the bride and a friend of the groom is mathematically represented as

$P(B \ n \ G) = \frac{20}{80}$

Now

$P(B|G)$ is mathematically represented as

$P(B|G) = \frac{P(B \ n \ G)}{P(G)}$

Substituting values

$P(B|G) = \frac{\frac{20}{80} }{\frac{30}{80} }$

$P(B|G) = \frac{2}{3}$

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3 years ago