Answer:
6/4
Step-by-step explanation:
#2. (-10, 0) (-10, -8) (0, -8)
#3. (-10, 0) (-10, 8) (-7, 8)
#4. (-10, 0) (-7, 0) (-7, 8)
#8. (0, 8) (0, 0) (8, 0) (10, 4)
#9. (-7, 0) (-7, 8) (0, 8) (0, 0)
#10. (-10, 0) (0, 0) (0, -8)
Not sure about the others. Hope this helps, though.
Answer:
Option D.
Step-by-step explanation:
In the figure attached, Diagonals AC and BD are bisecting each other at a point P.
That means AP ≅ CP and DP ≅ BP
We have to prove : AB ≅ DC and AB ║ DC
Proof : In triangles BPA and CPD,
AP ≅ CP
DP ≅ BP
∠ APB ≅ ∠DPC [vertically opposite angles]
Therefore, by postulate SAS [Side-Angle-Side]
ΔBCP ≅ ΔCDP
Option D. will be the answer.
Answer:
D
Step-by-step explanation: