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2 years ago

Rewrite the expression 18 with an exponent.

Mathematics

1 answer:

fredd [130]2 years ago

4 0

18^4 this is another way to show an exponent

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An angle is a figure formed by two? with a common?

Doss [256]

Yes ok it is with a common

6 0

2 years ago

Which is the difference of 21 1/4 - 18 2/4? A:2 1/4. B:2 2/4. C:2 3/4. D:3 1/4.

seropon [69]

Answer:

2 3/4 C

Step-by-step explanation:

$(21+\frac{1}{4})-(18+\frac{2}{4})\\=21-18+\frac{1}{4} -\frac{2}{4} \\=3-\frac{1}{4} \\=\frac{12-1}{4} \\=\frac{11}{4} \\=2\frac{3}{4} \\or\\21\frac{1}{4} -18\frac{2}{4} \\=\frac{85}{4} -\frac{74}{4} \\=\frac{85-74}{4} \\=\frac{11}{4} \\=2\frac{3}{4}$

3 0

3 years ago

On the first day of your garage sale, you earned 12x+9 dollars. The next day you earned 22x dollars. Is it possible you earned t

Mrac [35]

No, no value for x will result in you getting the same amount of money
I.e. on the first day if x =2 you earn 33. on the second day you would've earned 44. Of course this may be wrong so best to double check

4 0

2 years ago

Factor the trinomial x^2 - 16x +63

Butoxors [25]

Factor the following:
x^2 - 16 x + 63
The factors of 63 that sum to -16 are -7 and -9. So, x^2 - 16 x + 63 = (x - 7) (x - 9):
Answer: (x - 7) (x - 9)

3 0

3 years ago

Find the derivative of ln(cosx²).

RoseWind [281]

Answer:

$\displaystyle \frac{dy}{dx} = -2x \tan (x^2)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = \ln (\cos x^2)$

Step 2: Differentiate

Logarithmic Differentiation [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{(\cos x^2)'}{\cos x^2}$
Trigonometric Differentiation [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{-\sin x^2 (x^2)'}{\cos x^2}$
Basic Power Rule: $\displaystyle y' = \frac{-2x \sin x^2}{\cos x^2}$
Rewrite [Trigonometric Identities]: $\displaystyle y' = -2x \tan (x^2)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

8 0

2 years ago