The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Answer:
no
Step-by-step explanation:
-2 is less than 4 2/3
you can check this by looking at a number line
Answer:
A
Step-by-step explanation:
x=7
Answer:
a). 
m
b). 
m³
c). 
N²
Step-by-step explanation:
In this question we have to convert each option into SI units.
a). 
mm
= 
m
= m
b). (348 mm)³
= 
m³
= 
m³
= m³
c). 
N²
= 
N²
= 
= N²
