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3 years ago

What is the mean "6 5 6 1 5 5 0"

Mathematics

2 answers:

lesya692 [45]3 years ago

8 0

6+5+6+1+5+5+0=28
28/7=4
4 is the mean

yulyashka [42]3 years ago

4 0

Answer:

the mean is 4

Step-by-step explanation:

add 6+5+6+1+5+5+0=28

then divide 28 by how many numbers there are so it would be 7 numbers

28 divided by 7 equals 4

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Simplify 15(2/5+1 1/3)+3

loris [4]

So for order of operations you start inside the parentheses and in order to add the insides you will need a common denominator which would be 15 on the bottom. So for 2/5 it would be 6/15 and for 11/3 would be 55/15 and then added together it would be 61/15. so then you would multiply and get 15(61/15). the 15 in the numerator will cancel with the denominator leaving only 61 and then the final step would be adding the 3 to 61 and the final answer will be 64

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3 years ago

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Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number

Gnoma [55]

Sum/difference:

Let

$x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}$

This means that

$3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}$

Now, assume that $x$ is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that $x$ was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

$x = -15\sqrt{8}$

if again we assume x to be rational, we have

$\sqrt{8} = -\dfrac{x}{15}$

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0

3 years ago

Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1?

Degger [83]

The recursive formula $a_n = a_{n-1}-6$ can be used to generate the shown sequence

Step-by-step explanation:

Recursive formula is the formula that is used to generate the next term of a sequence using previous term.

The general form of arithmetic sequence's recursive formula is:

$a_n = a_{n-1}+d$

Given

5,-1,-7,-13,-19

Here

$a_1 = 5\\a_2 = -1\\a_3 = -7$

First of all we have to find the common difference of the sequence.

So,

$d = a_2 -a_1 = -1-5 = -6\\d = a_3-a_2 = -7+1 = -6$

Putting the value of d in the general recursive formula

$a_n = a_{n-1}-6$

Hence,

The recursive formula $a_n = a_{n-1}-6$ can be used to generate the shown sequence

Keywords: Sequence, arithmetic sequence

Learn more about arithmetic sequence at:

#LearnwithBrainly

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Does a linear equation have no solution, one solution, or infinitely many solutions?

Natasha_Volkova [10]

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