Answer:
The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
Step-by-step explanation:
The equation of the parabola is:

Compute the first order derivative of <em>y</em> as follows:

![\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bd%7Dy%7D%7B%5Ctext%7Bdx%7D%7D%3D%5Cfrac%7B%5Ctext%7Bd%7D%7D%7B%5Ctext%7Bdx%7D%7D%5B0.00035x%5E%7B2%7D%5D)

Now, it is provided that |<em>x </em>| ≤ 605.
⇒ -605 ≤ <em>x</em> ≤ 605
Compute the arc length as follows:


Now, let



Plug in the solved integrals in Arc Length and solve as follows:


Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
Answer:
38.5
Step-by-step explanation:
7/2 = 3.5. 11×3.5= 38.5
Answer:
y-(-1)=2/3(x-5)
Step-by-step explanation:
Point slope form is
y-y_1=m(x-x_1) where m is the slope, x_1 is the x coordinate of a point that the line passes through, and y_1 is the y coordinate of a point the line passes through.
Substituting, we get
y-(-1)=2/3(x-5)
Answer:
It doesn't. x = 22 271 201
Step-by-step explanation:
You are going to need a calculator no matter how you do it.

(a) The direct method

(b) The indirect method

Answer:
40/100=4/10=2/5 2/5 is the simplest form