What is 2 1/4 equal to

What is the solution of the system of equations?<br> y = 3x - 4<br> - 3y = -9x + 12

Mrac [35]

Answer:

infinitely many solutions

5 0

3 years ago

Answer as soon as possible

alexandr1967 [171]

Answer:

C −2a^3+9a^2+45a+6ab^2+18b^2

Step-by-step explanation:

(a+3) ( −2a^2+15a+6b^2)

Distribute the a to the large term in parentheses and the 3 to the large term in parentheses

a ( −2a^2+15a+6b^2)+3 ( −2a^2+15a+6b^2)

−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2

Combine like terms

−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2

-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2

3 0

2 years ago

Read 2 more answers

Question 2

FrozenT [24]

Answer:

y=-3x-1

Step-by-step explanation:

<u>Slope-intercept format:</u>

y = mx+b

m = slope

In this case, the slope is -3

b = y-intercept

In this case, the y-intercept is -1

Now we plug it in to get the equation:

y=-3x-1

I hope this helped!

Sincerely,

Rekifromsk8theinfinity

:D

3 0

2 years ago

Apply the markup for each item. Then, find the retail price. Round to two decimals places when necessary.

Alborosie

Answer:

$45 with 20% markup = $45 + $9 for a new total = $54

$7.60 with a 50% markup = $7.60 + $3.80 for new total = $11.40

Step-by-step explanation:

7 0

3 years ago

A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weig

jenyasd209 [6]

Answer:

$z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625$

The p value for this case would be given by:

$p_v =P(z$

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

Step-by-step explanation:

Information provided

$\bar X=19.87$ represent the sample mean

$\sigma=0.4$ represent the population deviation

$n=25$ sample size

$\mu_o =68$ represent the value that we want to test

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

The statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625$

The p value for this case would be given by:

$p_v =P(z$

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

7 0

2 years ago