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Alborosie
2 years ago
11

Real answers only pls! no links either!

Mathematics
1 answer:
fgiga [73]2 years ago
8 0

Answer:

C) 6/8+3/4

Step-by-step explanation:

1 16/32 = 1.5

6/8 = 0.75

3/4 = 0.75

0.75+0.75 = 1.5

Correct answer C)

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How many milliequivalents of sodium chloride are contained with 3 L of normal saline?
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Answer:

466mEq

Step-by-step explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

3000ml*\frac{0.9g}{100ml}=27g=27000mg

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation (mEq=\frac{mg}{pE}) where pE is de molecular mass of NaCl divided by their charges, in this case 1:

pE= \frac{23+35}{1}=\frac{58}{1} = 58

Finally we substitute in the mEq formula:

mEq=\frac{mg}{pE}=\frac{27000}{58}=466mEq

I hope you find this information useful! Good luck!

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3 years ago
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