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3 years ago

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The movie theater kept track of how many tickets the sold on Wednesday.choose the best title for the data. A.tickets sold. B.sca

riest movie. C.tickets cost. D.favorite movie

1 answer:

Shkiper50 [21]3 years ago

3 0

Answer:

A. Tickets sold

The table says nothing about the scariest movie, the favorite movie, or the cost of the tickets.

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Line segment XY begins at (-6,4) and ends at (-2,4). The segment is reflected over the x-axis and translated left 3 units to for

Marat540 [252]

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Line segment XY begins at (-6,4) and ends at (-2,4). Hence:

$XY = \sqrt{(4-4)^2 + (-2 +6)^2} \\\\XY = \sqrt{0+16} \\\\XY = \sqrt{16} \\\\XY = 4$

XY is reflected over the x-axis and translated left 3 units to form line segment X'Y'. Hence:

XY = X'Y' = 4 units

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

Find out more on equation at:

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5 0

2 years ago

K(a)= 4a-4, Find k(-9)

FromTheMoon [43]

We simply replace a with -9

k(-9) = 4 * -9 - 4

k(-9) = -40

:)

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2

saul85 [17]

$\large\underline{\sf{Solution-}}$

<u>Let us assume that:</u>

$\sf \longmapsto x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ... \infty } } }$

We can also write it as:

$\sf \longmapsto x = \sqrt{6 + x }$

Squaring both sides, we get:

$\sf \longmapsto {x}^{2} =6 + x$

$\sf \longmapsto {x}^{2} - x - 6 =0$

By splitting the middle term:

$\sf \longmapsto {x}^{2} - 3x + 2x - 6 =0$

$\sf \longmapsto x(x - 3) + 2(x - 3 ) =0$

$\sf \longmapsto (x+ 2)(x - 3 ) =0$

<u>Therefore:</u>

$\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}$

$\sf \longmapsto x = - 2,3$

<u>But x cannot be negative. </u>

$\sf \longmapsto x = 3$

Therefore, the value of the expression is 3.

$\large\underline{\sf{Verification-}}$

Given:

$\sf\longmapsto x=3$

We can also write it as:

$\sf\longmapsto x = \sqrt{9}$

$\sf\longmapsto x = \sqrt{6+3}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{9}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}$

This pattern will continue.

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}$

7 0

3 years ago

Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $2,783 was collected on the sale of 1,235 ticket

choli [55]

A = the number of adult tickets

S = the number of student tickets

[you can use different variables x, z, t, etc...]

5A + S = 2783 [$5 per adult plus $1 per student = total $2783]

A + S = 1235 [# of adults plus # of students = 1235]

To find A and S, you need to do substitution. First isolate one of the variables using either one of the equations, I will isolate the A in A + S = 1235:

A + S = 1235 Subtract S on both sides of the equation

A = 1235 - S

Next substitute/plug in (1235 - S) for A to find the value of S:

5A + S = 2783 [isolate/get S by itself in the equation]

5(1235 - S) + S = 2783 Distribute/multiply 5 into (1235 - S)

(5)1235 - (5)S + S = 2783

6175 - 5S + S = 2783 Combine like terms (-5s and S)

6175 - 4S = 2783 Subtract 6175 on both sides

-4S = -3392 Divide -4 on both sides

S = 848

Now that you found S, you can use it to find A:

A + S = 1235

A + 848 = 1235 Subtract 848 on both sides

A = 387

S = 848 student tickets

A = 387 adult tickets

6 0

3 years ago

-2x + y = 4<br> y = x + 2<br><br><br> Third question^ solve the system of equations

Leya [2.2K]

Answer:

x=-2 y=0

Step-by-step explanation:

put the second equation in to the first one

-2x+x+2=4

-x=2

x=-2

y=-2+2=0

x=-2 y=0

6 0

3 years ago