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lawyer [7]
3 years ago
9

348.562 in expanded form:

Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer:

300 plus 40 plus 8 plus 0.5 plus 0.06 plus 0.002

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Step by step show answer for problem 3-3×6+2
storchak [24]
Do it according to the order of operations
(P)E^MxD/A+S-
the answer would be     -13

4 0
3 years ago
Read 2 more answers
Adam’s sister wants to watch her intake of fat per day. He estimates that the dinner will have 48 grams of fat. What percentage
navik [9.2K]
First things to take note of to have the correct answer: 
1. Adam's sister is obviously a girl. Then when looking at the data we look at the "Women" column. 
2. We are only looking at the fats data. 

We are asked for the percentage given 48 grams of fat and the daily allowance on fat for women is 70 g. To solve we perform the operation: 

% =  \frac{70-48}{70} * 100 = 31.42% ≈ 31%
3 0
3 years ago
Is the relationship shown by the data linear? If so, model the data with an equation.
Svet_ta [14]
Yes it is linear, you go up my fours in the y side and go down by two on the x side. The equation is y=2x+19
4 0
3 years ago
PÕQ = 40°? [WAEC] A pie chart is divided into four sectors as shown in Fig. 12.46. Each sector represents a percentage of the wh
Serhud [2]

Answer:

126°

Step-by-step explanation:

the total max percent can be 100%

OR

The total value of the pie is 100%

that means all sectors must add upto 100

=> x + x + 21 + 9 = 100

=> 2x + 30 = 100

=> 2x = 70

=> x = 35

therefore, the two large sectors which are both equal to x each represents 35% of the whole.

<u>Angle subtended by one of those large sectors</u> :-

\theta  =  \frac{component \: part}{total}  \times 360

=  \frac{35}{100}  \times 360 \\  = 126

therfore, the central angle of the big sector is<u> 126°</u>

6 0
3 years ago
Couple has got 5 children , what is the probability of have 3girls and 2 boys ?
Delicious77 [7]
5 children so you have 2^5=32 possibilities to "assign" genders
P(3 girls):
how many possibilities are there to "assign" the 3 girl-genders to the 5 children? the first girl has 5 possibilities then the next 4, 3 -> 5*4*3=60
but these possibilities include orders of assigned genders, while children 1-5 might differ the gender "girl" is always the same so we have the remove the orderings of the 3 girl-gender assignments which is 3*2*1=6
if we divide 60/6 we get 10 possibilities to have 3 girls, so what is the resulting chance? the 10 possibilities divided by the total 32 possibilities: 10/32=5/16=P(3 girls)=P(2 boys)

this is a bit of lengthy way of saying "use the binomial coefficient" equation/explaining it a bit which is (n!)/(k!(n-k)!) with n=5, k=3:
5*4*3*2*1/((3*2*1)*(2*1))=
5*4*3*2/(3*2*2)=
5*4*3*2/(3*4)=
5*2=
10 possibilities again


P(girls>=4)=P(boys<=1)=P(boys=1)+P(boys=0)
(or P(girls=4)+P(girls=5))

P(boys=0) is the easy case: simply multiply the chance of getting a girl 5 times: (1/2)^5=1/32
P(boys=1)= again the binomial coefficient with n=5 and k=1:
5*4*3*2*1/((1)*(4*3*2*1))=
5*4*3*2/(4*3*2)=
5 possibilities
so the P(boys=0)=1 possibility + P(boys=1)=5 possibilities totals to 6 possibilities
again the chance is the 6 possibilities divided by all 32 possibilities: 6/32=3/16

P(alternate gender starting with boy): when thinking about the possibilities then there is only a single way to build that order: bgbgb, so one possibility
knowing there is only one way we already know P(alternate...)=1/32 by again dividing by the total amount of possibilities
the alternative way would be to multiply P(boy)*P(girl)*P(boy)*P(girl)*P(boy)=(1/2)^5= 1/32 again





5 0
3 years ago
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