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lawyer [7]
3 years ago
9

348.562 in expanded form:

Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer:

300 plus 40 plus 8 plus 0.5 plus 0.06 plus 0.002

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Help meh?
zloy xaker [14]
X= # of miles
.55x+1.75 is greater than or equal to 10

So if she has to go more than 2 miles we will put 2 in for X

.55(2)+1.75 is greater than or equal to 10
.55×2= 1.10+1.75= 2.85
2.85 is greater than 10 is false so now we know she has to go more than 2 miles.

Let's guess and check. Now let's say 15 miles
.55×15= 8.25+1.75= 10
10=10 So she needs to drive at least 15 miles

x is greater than or equal to 15

Please don't solely rely on my answer I don't know if it's correct
3 0
3 years ago
The graph of F(x) shown below has the same shape as the graph of G(x) = x^2 but it is shifted down 5 units and to the left 4 uni
grandymaker [24]

\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}\\ ~~~~~~\textit{reflection over the x-axis}

\bf \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}\\\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}


with that template in mind, let's see

down by 5 units, D = -5

to the left by 4 units, C = +4


\bf G(x)=x^2\implies G(x)=1(1x+\stackrel{C}{0})^2+\stackrel{D}{0} \\\\\\ \begin{cases} D=-5\\ C=+4 \end{cases}\implies F(x)=1(1x+\stackrel{C}{4})^2\stackrel{D}{-5}\implies F(x)=(x+4)^2-5

5 0
2 years ago
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