Answer:
I think you need to attach something
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
The mean is 6 and there are 5 intergers.
You'd multiply 5*6=30. That means that the sum is 30.
The values could be: 2 3 7 9 9
These values add up to 20
Have a mode of 9
Have a median of 7
Have a mean of 6
To find the range you would subtract 9 and 2. That gives you 5.
(i don't know if that's the greatest possible range. But 5 would be the range here)
1 over 3 since its rise over run and the x would be on the bottom and since you dont have a y it would be 1
If you’re solving for a... subtract the 8 to the other side so...
-4(a+3)- 3(2a-8) = 22.
Distribute the -4 and -3 into the parentheses (two negatives multiplied together is a positive)...
-4a-12-6a+24 = 22.
Add the constants and a’s together.
-10a + 12 = 22
Subtract 12 to the other side.
-10a = 10
Divide both sides by -10.
a = -1
Check and make sure that this answer works with the problem.
-4(-1+3)-3(-2-8)=22
-4(-2)-3(-10)=22.
-8+30=22.
22=22, the answer checks out
A_n= a₁ rⁿ⁻¹
a₁ is the first term
r= common ratio
a_n=2(2)²⁰⁻¹= 1048576
