C^5m^3 would be the simplified form of your problem. Hope this helps! ^-^
Answer:
7 years 11 months
Step-by-step explanation:
The future value formula for the value of a principal P invested at annual rate r compounded n times yearly for t years is ...
FV = P(1 +r/n)^(nt)
For the given numbers, we want to find t:
6000 = 3700(1 +.062/2)^(2t)
Dividing by 3700 and taking the logarithm, we get ...
6000/3700 = 1.031^(2t)
log(60/37) = 2t·log(1.031)
Dividing by the coefficient of t gives ...
t = log(60/37)/(2log(1.031)) ≈ 7.92 . . . . . years
It will take about 7 years 11 months for the investment to grow to $6000.
Answer:
Your question but don't know how to solve it like a dog
[x-1]=5x+10
We have two equations:
1) x-1=5x+10
x-1=5x+10
x-5x=10+1
-4x=11
x=-11/4
2) x-1=-(5x+10)
x-1=-(5x+10)
x-1=-5x-10
x+5x=-10+1
6x=-9
x=-9/6=-3/2
we have two possible solutions:
solution₁; x=-11/4
solution₂: x=-3/2
we check it out:
1) x=-11/4
[x-1]=5x+10
[-11/4 - 1]=5(-11/4)+10
[(-11-4)/4]=-55/4 + 10
[-15/4]=(-55+40) /4
15/4≠-15/4 This solution don´t work.
2) x=-3/2
[x-1]=5x+10
[-3/2 - 1]=5(-3/2)+10
[(-3-2)/2]=-15/2 + 10
[-5/2]=(-15+20)/2
5/2=5/2; this solution works.
Therefore:
Answer: x=-3/2.
Answer:182/7g
Step-by-step explanation: 182 divide by 7= 26
342 divide by 9=38
and you want the lowest cost so a.
