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Readme [11.4K]
2 years ago
9

Simplify (1/4 ad^3)^2

Mathematics
1 answer:
Dima020 [189]2 years ago
7 0
That "ad^3" bothers me; I'm not sure what you mean here.

I'm going to assume that you have     (1/4*a*d^3)^2.

If that's the case, then you have (1/4)^2 * a^2 * d^6 = (1/16)*a^2*d^6.

If this is not what you were hoping for, double check to ensure that you have copied down this problem exactly as it was presented.


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What is the best metric unit to use for the mass of a grasshopper
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♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷The best metric unit to use for the mass of a grasshopper is grams, because a grasshopper is very light and a gram is small.

One gram is about the weight of a paper clip or a butterfly.

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6 0
2 years ago
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Simplify the following problem.<br> (-8+61) +(6+61)
Travka [436]

Answer: -8+61 = 53 and 6+61 = 67

3 0
2 years ago
A high school spends approximately $9,000 hosting a football games (e.G. The hourly pay for staff, the electricity, water usage,
Yanka [14]

Answer:

<u>$4800</u>

Step-by-step explanation:

The expected net income is the probability when rains multiplied by net income (profit) summed with the probability of not raining with that days net income multiplied.

First, Chance of rain = 12% = 12/100 = 0.12

Profit/Loss = Income - Cost

Income is 5000

Cost = 9000

So,

Loss = 5000 - 9000 = 4000

Or, Net Income (profit) = - 4000

Now, Change of not raining = 100 - 12 = 88% = 88/100 = 0.88

Profit = Income - Cost

Income = 15,000

Cost = 9000

Net Income (profit) = 15000 - 9000 = 6000

So, we can write the expected net income as:

<u>Expected NI </u>= (0.12)(-4000) + (0.88)(6000) = <u>$4800</u>

8 0
2 years ago
In a sample of n = 6 scores, 5 of the scores are each above the mean by one point. Where is the 6th score located relative to th
den301095 [7]

The mean of a dataset is the sum of all data elements divided by the count of the elements.

The location of the 6th score relative to the mean is 5 points below the mean

Let:

\bar x \to<em> Mean</em>

a \to<em> 5 scores</em>

b \to<em> 6th scores</em>

Given that:

n = 6

The 5 scores that are 1 above the mean implies that:

a = \bar x + 1

The mean of a dataset is calculated using:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x =\frac{5a + b}{6}

\bar x =\frac{5(\bar x + 1) + b}{6}

Open brackets

\bar x =\frac{5\bar x + 5 + b}{6}

Multiply both sides by 6

6\bar x =5\bar x + 5 + b

Make b the subject

b = 6\bar x -5\bar x - 5

b = \bar x - 5

This means that the 6th score is 5 points below the mean

Read more about mean at:

brainly.com/question/17060266

3 0
2 years ago
Write a function using function notation to describe each situation. Find a reasonable domain and range for each function.
sergejj [24]
F(t)= 7.00 x t + 55 A reasonable domain is (0,1,2,3). The range is ($55,$62,$69,$76)
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