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Ad libitum [116K]
3 years ago
6

A golden rectangle has a length of 5 cm. Find the area of the rectangle to the nearest square centimeter.

Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer: is it 25? i am bad at math but i am guessign

Step-by-step explanation:

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Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appea
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Answer:

0.2

Step-by-step explanation:

If two number cubes as tossed then the total possible out comes are

Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

Number of elements in sample space are

n(S)=36

Let A and B represent the following events.

A = The sum will be 4.

A = {(1,3),(2,2),(3,1)}

n(A) = 3

B = The sum is less than or equal to 6.

B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

n(B)=15

Intersection of both events is

A∩B = {(1,3),(2,2),(3,1)}

n(A∩B) = 3

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{36}

P(B)=\dfrac{n(B)}{n(S)}=\dfrac{15}{36}

P(A\cap B)=\dfrac{n(A\cap B)}{n(S)}=\dfrac{3}{36}

We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.

P(\frac{A}{B})=\dfrac{P(A\cap B)}{P(B)}

P(\frac{A}{B})=\dfrac{\frac{3}{36}}{\frac{15}{36}}

P(\frac{A}{B})=\dfrac{3}{15}

P(\frac{A}{B})=\dfrac{1}{5}

P(\frac{A}{B})=0.2

Therefore, the required probability is 0.2.

3 0
3 years ago
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