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NISA [10]
3 years ago
14

Please help me i will mark brilient​

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0
<h2>Solution:</h2>

\red{20 \:  \frac{1}{4}  \div 9}

=  \frac{81}{4}  \div 9

=  \frac{^{9}\cancel{81}}{4}  \times  \frac{1}{\cancel{9}^{1} }

=  \frac{9}{4}

\blue{ =  \boxed{2 \:  \frac{1}{4} }}

<h2>Answer:</h2>

<u>2</u><u> </u><u>¼</u><u> </u><u>m</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>l</u><u>e</u><u>n</u><u>g</u><u>t</u><u>h</u><u> </u><u>o</u><u>f</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>p</u><u>i</u><u>e</u><u>c</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>o</u><u>p</u><u>e</u>

<h2>=============================</h2>

Hope it helps

<h2>=============================</h2>
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Please can someone help me please
Tomtit [17]
You can use variables to solve this problem. Lets say that m is men, w is women, and c is children. m+w+c=266
four times as many men as children in ‘math words’ would be 4c=m
twice as many women as children would be 2c=w
what we can do now is plug those in to make everything easier with one variable
4c+2c+c=266
7c=266
c=38 now we have how many children, and we need to plug it back into what we have for women and men.
4c=m 4(38)=m m=152
2c=w 2(38)=w w=76


152 men, 76 women, and 38 children
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3 years ago
If y varíes directly as x, and x=1/4 when y =6 , what is the value if x when y =30
hram777 [196]
45 is y and 25 is x is you answer ok
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Simplify 4a + 5a + 6b + 3b
Katarina [22]

Step-by-step explanation:

4a + 5a + 6b + 3b

=9a + 9b

= 9(a+b)

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3 years ago
Determine which of the following are functions. Select all that apply. A 2-column table with 5 rows. Column 1 is labeled x with
iragen [17]

Answer:

Step-by-step explanation:

no.

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3 years ago
Read 2 more answers
What is the simplified form of this expression? (4x − 4) − 8x A. -8x B. 12x − 4 C. -4x + 4
valentinak56 [21]

Answer:

None; -4x-4

Step-by-step explanation:

(4x - 4) - 8x

=4x - 4 - 8x

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