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Vesna [10]
3 years ago
5

Please can someone help me please

Mathematics
1 answer:
Tomtit [17]3 years ago
7 0
You can use variables to solve this problem. Lets say that m is men, w is women, and c is children. m+w+c=266
four times as many men as children in ‘math words’ would be 4c=m
twice as many women as children would be 2c=w
what we can do now is plug those in to make everything easier with one variable
4c+2c+c=266
7c=266
c=38 now we have how many children, and we need to plug it back into what we have for women and men.
4c=m 4(38)=m m=152
2c=w 2(38)=w w=76


152 men, 76 women, and 38 children
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Answer:

a. 40320 ways

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Step-by-step explanation:

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No. of ways to arrange the 8 jobs = 8!

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b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

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c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

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Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

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<span>That's 9(10)(10)(10)2=18,000
</span>
I hope this helps. 
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