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Vesna [10]
3 years ago
5

Please can someone help me please

Mathematics
1 answer:
Tomtit [17]3 years ago
7 0
You can use variables to solve this problem. Lets say that m is men, w is women, and c is children. m+w+c=266
four times as many men as children in ‘math words’ would be 4c=m
twice as many women as children would be 2c=w
what we can do now is plug those in to make everything easier with one variable
4c+2c+c=266
7c=266
c=38 now we have how many children, and we need to plug it back into what we have for women and men.
4c=m 4(38)=m m=152
2c=w 2(38)=w w=76


152 men, 76 women, and 38 children
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IF a= 6 and b= 7, then 4a(3b+5) + 2b =?
lukranit [14]

Answer:

64

Step-by-step explanation:

4a(3b+5)+2b

Substitution

4(6)[3(7)+5]+2(7)

Order of operations (PEMDAS)

4(6)[21+5]+2(7)

4(6)+26+2(7)

24+26+14

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64

Hope this helps. Have a nice day. May it be filled with joy and happiness. Please, be safe and wash your hands. Happy Holidays.

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3 years ago
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shutvik [7]
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y=26-x( substitute this into second equation for y and solve for x)

4.75x + 2.25(26-x)= 83.50

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Answer:

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Step-by-step explanation:

As 0.644 and 0.25 are less than 1, then

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