All categories

2 years ago

Evaluate 2x-5x+ 12 when x = -2

Mathematics

2 answers:

vodka [1.7K]2 years ago

7 0

Answer:

2(-2)-5(-2)+12

-4-(-10)+12

6+12

Step-by-step explanation:

wel2 years ago

7 0

Answer:

Step-by-step explanation:

2(-2)-5(-2)+12

-4+10+12

=18

Hope this helps! ;-)

You might be interested in

Which is better, a really good desert, or a really yummy dinner? What is your favorite?

bearhunter [10]

Both cause u get some nice dinner then right after u get some nice desert. I just like food so I like anything

8 0

3 years ago

Read 2 more answers

If ABC =30o , what is the measure of its complement CBD

Fantom [35]

It would be 60 degrees because compliment means 90 degrees. In order to find m<CBD, you would need to subtract 30 degrees from 90 degrees which would equal 60 degrees. 90-30=60

5 0

3 years ago

Find slope of -2,3 and 4,-5

bulgar [2K]

-2,3 is (x1,y1) and (4,-5) is (x2,y2) so you do y2-y1/x2-x1

y2-y1 is -5-3 which is -8 and x2-x1 is 4-(-2) which is 6 so you get

-8/6= -4/3

4 0

3 years ago

What is the distance between point A and point B?

DIA [1.3K]

The answer is possibly 10

4 0

3 years ago

Read 2 more answers

A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$

$x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i$

The solutions are:

$x=3i,\:x=-3i$

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor $x^2+9$ :

First, multiply the constant in the polynomial by $i^2$ where $i^2$ is equal to -1.

$x^2+9i^2$

Since both terms are perfect squares, factor using the difference of squares formula

$a^2-i^2=(a+i)(a-i)$

$x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)$

5 0

3 years ago