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WINSTONCH [101]
3 years ago
8

Which distinguishes a dwarf planet from a planet?

Chemistry
2 answers:
Rashid [163]3 years ago
6 0

Answer:

It's size

Explanation:

The definition of a dwarf planet is "a celestial body that orbits the sun and has a spherical shape but is not large enough to disturb other objects from its orbit"

Essentially, "dwarf" is an adjective. Just like saying the colour distinguishes a purple planet...

katrin [286]3 years ago
3 0
Dwarf = too small to be a planet
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Name two bases which react with dillute sulfuric acid to give zinc sulfate
IRINA_888 [86]

Answer:

Zinc Carbonate

Zinc Nitrate

Explanation:

8 0
3 years ago
Consider the following unbalanced redox reaction:
Olegator [25]
Mn04 is being reduced
5 0
3 years ago
assume you have a 500 g sample of a radioactive isotope with a half-life of 100 years. fill in the table showing how many grams
sweet-ann [11.9K]

Answer:

8.10 hours.

Explanation:

You start with 500.0g.

After the first half-life, you have 250.0g.

After the second, you have 125.0g.

After the third, you have 62.50g.

Therefore, it takes three half-lives to decay to 62.50g.

Therefore, the elapsed time must be triple the length of one half-life.

24.3

3

=

8.10

, so it is 8.10 hours.

Explanation:

3 0
3 years ago
Read 2 more answers
10. a. What is the binding energy released when an alpha particle of mass 6.64 x 10-27 kg escapes from the nucleus of Uranium- 2
shutvik [7]

Answer:

The binding energy released is 1.992 X 10⁻¹⁸ J

Explanation:

Given;

mass of the alpha particle, m = 6.64 x 10⁻²⁷ kg

speed of the alpha particle, c = 3 x 10⁸ m/s

The binding energy released is given by;

E_b = mc^2

where;

m is mass of the particle

c is speed of the particle

E = 6.64 x 10⁻²⁷ (3 x 10⁸)²

E = 1.992 X 10⁻¹⁸ J

Therefore, the binding energy released is 1.992 X 10⁻¹⁸ J

7 0
3 years ago
A sample of gas has a pressure of 100.0 KPa and 25C. Calculate the pressure if the temperature is changed to 125C while the volu
atroni [7]

Answer:

133.56kPa

Explanation:

Applying Pressure Law,

P/T = P'/T'....................... Equation 1

Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.

From the question, we were asked to calculate P'

There, we make P' the subject of the equation

P' = PT'/T...................... Equation 2

Given: P = 100kPa, T = 25°C = (273+25) = 298K, T' = 125°C = (273+1250K = 398 K

Substitute these values into equation 2

P' = (100×398)/298

P' = 133.56kPa

Hence the pressure is 133.56kPa

6 0
3 years ago
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