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Lynna [10]
3 years ago
10

Explain why Figure B is not the image of Figure A after a reflection using linel, A​

Mathematics
1 answer:
NARA [144]3 years ago
5 0
There is no image or png..
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Which is a factor of 21 <br> a6 <br> b5 <br> c4 <br> d3
aev [14]
3 because 7*3=21,...........
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3 years ago
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Would someone just answer this now anyone?
brilliants [131]
Look up range in the calculator
6 0
3 years ago
How do you do number 1?<br>Whenever I tried to answer it, I always get fraction. help me.​
Flura [38]

Answer:

The pairs are (13,15) and (-15,-13).

Step-by-step explanation:

If n is an odd integer, the very next odd integer will be n+2.

n+1 is even (so we aren't using this number)

The sum of the squares of (n) and (n+2) is 394.

This means

(n)^2+(n+2)^2=394

n^2+(n+2)(n+2)=394

n^2+n^2+4n+4=394               since (a+b)(a+b)=a^2+2ab+b^2

Combine like terms:

2n^2+4n+4=394

Subtract 394 on both sides:

2n^2+4n-390=0

Divide both sides by 2:

n^2+2n-195=0

Now we need to find two numbers that multiply to be -195 and add up to be 2.

15 and -13 since 15(-13)=-195 and 15+(-13)=2

So the factored form is

(n+15)(n-13)=0

This means we have n+15=0 and n-13=0 to solve.

n+15=0

Subtract 15 on both sides:

n=-15

n-13=0

Add 13 on both sides:

n=13

So if n=13 , then n+2=15.

If n=-15, then n+2=-13.

Let's check both results

(n,n+2)=(13,15)

13^2+15^2=169+225=394.  So (13,15) looks good!

(n,n+2)=(-15,-13)

(-15)^2+(-13)^2=225+169=394.  So (-15,-13) looks good!

6 0
3 years ago
Geometric sequences HELP ASAP!
Pani-rosa [81]

Given:

The table for a geometric sequence.

To find:

The formula for the given sequence and the 10th term of the sequence.

Solution:

In the given geometric sequence, the first term is 1120 and the common ratio is:

r=\dfrac{a_2}{a_1}

r=\dfrac{560}{1120}

r=0.5

The nth term of a geometric sequence is:

a_n=ar^{n-1}

Where a is the first term and r is the common ratio.

Putting a=1120, r=0.5, we get

a_n=1120(0.5)^{n-1}

Therefore, the required formula for the given sequence is a_n=1120(0.5)^{n-1}.

We need to find the 10th term of the given sequence. So, substituting n=10 in the above formula.

a_{10}=1120(0.5)^{10-1}

a_{10}=1120(0.5)^{9}

a_{10}=1120(0.001953125)

a_{10}=2.1875

Therefore, the 10th term of the given sequence is 2.1875.

6 0
3 years ago
1. Subtract (7 – 19i) from (–6 + 12i). A. –13 – 31i B. –13 + 31i C. 13 – 31i D. 13 + 31i
pav-90 [236]

Answer:

Step-by-step explanation:

(-6+12i)-(7-19i)=

-6+12i-7+19i=

-13+31i

(b)

6 0
3 years ago
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