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lapo4ka [179]
3 years ago
10

Please hurry this is urgent like I need to submit RIGHT NOWWW PLEASEEE

Mathematics
1 answer:
vaieri [72.5K]3 years ago
4 0

Answer:

I'm sorry m8, but the picture won't load, what is it? The screen is just black

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What is the value of x?<br> Enter your answer, as a decimal, in the box.<br> ft
Lilit [14]

Answer:

67.5 ft.

Step-by-step explanation:

Length of MA = 71.5 - 22 = 49.5 ft.

Length of BP  = 97.5 - x.

So we have the equation:

22 / 49.5 = (97.5- x) / x

Cross multiply:

22x = 49.5(97.5 - x)

22x = 4826.25 - 49.5x

22x + 49.5x = 4826.25

71.5x = 4826.25

x = 4826.25/71.5

x= 67.5 ft.

6 0
3 years ago
What's 1/16 divided by 3/8? please help​
sattari [20]

Hello from MrBillDoesMath!

Answer:

1/6

Discussion:

(1/16) / (3/8) =              =>   1/(1/a) = a!

(1/16) * (8/3) =

(8/16) * (1/3)  =             => as 8/16 = 1/2

(1/2) * (1/3) =

1/6

Thank you,

MrB

6 0
3 years ago
Verify the pythagorean identity 1 + c o t ^2 θ = c s c ^2 θ
Grace [21]

Answer: The identity is verified. See the explanation.

Step-by-step explanation:

You must keep on mind the following identities:

csc\theta=\frac{cos\theta}{sin\theta}\\\\csc\theta=\frac{1}{sin\theta}\\\\sin^2\theta+cos^2\theta=1

Therefore, by substitution, you can rewrite the identity as shown below:

1+cot^2\theta=csc^2\theta\\\\1+\frac{cos^2\theta}{sin^2\theta}=csc^2\theta

Simpliying, you obtain:

\frac{sin^2\theta+cos^2\theta}{sin^2\theta}=csc^2\theta\\\\\frac{1}{sin^2\theta}=csc^2\theta\\\\csc^2\theta=csc^2\theta

The identity is verified.

6 0
3 years ago
the ratio of the number of adults to the number of students at the problem has to be 1 :10 Last year there were 477 more student
JulsSmile [24]
About 48 adults. I think.
4 0
3 years ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
mamaluj [8]

Answer:

Systolic variation coefficient (CVS) = 0.1446 = 14.46%

Diastolic variation coefficient (CVD) =  0.1789 = 17.89%

The variation, with respect to the mean, of the systolic pressure sample is slightly less than the variation of the Diastolic pressures.

Step-by-step explanation:

Systolic Mean (MS) = 127.8

Diastolic Mean (MD) = 73.5

Standard Deviation Systolic (sdS) = 18,486

Standard Deviation Diastolic (sdD) = 13.1508

The coefficient of variation is defined by:

Systolic variation coefficient (CVS) = sdS / MS = 18.486 / 127.8 = 0.1446 = 14.46%

Diastolic variation coefficient (CVD) = sdD / MD = 13.1508 / 73.5 = 0.1789 = 17.89%

Then, it can be concluded that the variation, with respect to the mean, of the systolic pressure sample is slightly less than the variation of the Diastolic pressures.

8 0
3 years ago
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