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3 years ago

Write an equation in slope-intercept form of the line that passes through the given point and is

Mathematics

1 answer:

Tema [17]3 years ago

5 0

Answer:

y = 9x - 15

Step-by-step explanation:

The given y = 9x - 5 is already in slope-intercept form. Any line parallel to this one has an equation that looks exactly the same except for the constant term. Call the new constant term 'C.'

Start with y = 9x - 5 and substitute the coordinates of the given point (-1, 6):

6 = 9(-1) + C, or

6 + 9 = C, or

C = 15

Then the equation of the line that passes through (-1, 6) and is parallel to y = 9x - 5 is

y = 9x - 15

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Point O is between points Mand N on line segment MN. O is the midpoint of line segment MN if

s2008m [1.1K]

Diagram:
M------------O-------------N
................. ^ midpoint
Obviously if O is the *mid*point, then it is exactly halfway between M and N. That also means it has bisected the segment into two equal parts.
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3 years ago

What is the length of the side opposite 3 units<br> 4 units<br> 5 units<br> 6 units<br> 0

sleet_krkn [62]

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Step-by-step explanation:

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3 years ago

Pls solve part b) iii thanks

Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees