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Marysya12 [62]
3 years ago
13

HELP PLEASE ASAP (no links scammers) WILL GIVE BRAINLEAST (again NO LINKS)

Mathematics
1 answer:
Sophie [7]3 years ago
8 0
B) Because 4/24 is the amount of cars
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I really need help with this question!
ololo11 [35]
Same as all the other ones like this.

Since the two figures are similar . . .

-- The ratio of of their volumes is  R³ .

-- The ratio of their surface areas is  R² .

-- The ratio of their dimensions is  R .

So  R³  is        729 / 2744 .

Take the cube root of that and you'll have  R .

Then square R and you'll have the ratio of their surface areas.
5 0
3 years ago
Steve picks 55 pounds of pears. He packs an equal amount of pears into 6 bags. He then has 4 pounds of pears left. What is the w
Serggg [28]
Because he has 4 pounds of apples left, you are to subtract that from the total pounds picked, which was a total of 55 pounds. So 55 with 4 taken away, or 55 - 4, equals 51. Since he had equally put 51 pounds into six bags, you are to then divide . 51 / 6 = 8.5. He had put 8.5 pounds worth of apples into each bag.
4 0
3 years ago
Read 2 more answers
25/3 ÷ x = 7/3 ÷8.1<br><br> I don't get it, what's the answer??
Viktor [21]

Answer:

x=28.93(rounded) x=28.929(not rounded)

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A report on consumer financial literacy summarized data from a representative sample of 1,664 adult Americans. Based on data fro
daser333 [38]

Answer:

a. The 95% confidence interval for the proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is (0.54, 0.588). This means that we are 95% sure that the true proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is between these two bounds.

b. Because this confidence interval is entirely above 0.5, the interval is consistent with the statement that a majority of adult Americans would give themselves a grade of A or B.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Sample of 1,664 adult Americans, 939 people in the sample would have given themselves a grade of A or B in personal finance.

This means that n = 1664, \pi = \frac{939}{1664} = 0.5643

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5643 - 1.96\sqrt{\frac{0.5643*0.4357}{1644}} = 0.54

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5643 + 1.96\sqrt{\frac{0.5643*0.4357}{1644}} = 0.588

The 95% confidence interval for the proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is (0.54, 0.588). This means that we are 95% sure that the true proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is between these two bounds.

(b) Is the confidence interval from part (a) consistent with the statement that a majority of adult Americans would give themselves a grade of A or B?

Yes, because the confidence interval is entirely above 0.5.

Because this confidence interval is entirely above 0.5, the interval is consistent with the statement that a majority of adult Americans would give themselves a grade of A or B.

8 0
3 years ago
Please help me with these two.
Bad White [126]

Just 9

I'm not sure for the second one but I think 1 ft

3 0
3 years ago
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