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dedylja [7]
3 years ago
14

There is a sidewalk of width x around a rectangular garden. If the garden measures twenty-feet by thirty-feet, then the combined

area of the garden and sidewalk is
Mathematics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

Area = 200 + 50 + x

Step-by-step explanation:

Given

Length = 20

Width = 30

Side Walk = x

Required

Determine the area.

To do this we need to get the new worth and length by adding the length of the sidewalk.

This gives:

Length = 20 + x.

Width = 30 + x

So, area becomes.

Area = (20 + x)(30 + x)

Area = 600 + 20x + 30x + x²

Area = 200 + 50 + x²

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In a typical children's soccer game, there is one goal scored approximately every 18 minutes. The number of goals scored follows
Alja [10]

Answer:

2.24

Step-by-step explanation:

The probability formula using a Poisson distribution is:

P(k\ events) = \frac{\lambda^{k}e^{-\lambda}}{k!} \\\lambda\ is\ the\ average\ number\ of\ events\ per\ interval \\e\ is\ euler's\ number \\k\ is\ the\ number\ of\ events\ you\ want\ to\ calculate

λ = 90 / 18 = 5 average goals per interval (interval = a game)

So if for example you were interested in the probability of making 2 goals in a game

k = 2

P(k = 2) = \frac{5^{2}e^{-5}}{2!} = 0.084

This was just an example,

The standard deviation is \sqrt{\lambda}

\sigma = \sqrt{\lambda} \\\sigma = \sqrt{5} \\\sigma = 2.24

8 0
3 years ago
Daniel's goal is to walk 100 miles.• He walks 5 miles every day.• He has
lozanna [386]

Answer:

65 miles

Step-by-step explanation:

Given:

  • k = how many more miles Daniel has to walk
  • Goal = 100 miles
  • Daily miles = 5 miles
  • Number of days already walked = 7 days

Equation:

5 × 7 + k = 100

Solving:

⇒ 5 × 7 + k = 100

⇒ 35 + k = 100

⇒ k = 100 - 35

⇒ k = 65

3 0
2 years ago
Does any one understand number one ? And how do you do it ?
alexdok [17]
Here are the answers for the HW:

6 0
2 years ago
What percent of 18.75 is 27?
Olin [163]
The answer is 144%





Your welcome

4 0
3 years ago
How do I solve these problems? ln(x) = 5.6 + ln(7.5) and log(x) = 5.6 - log(7.5)
SOVA2 [1]

Use the rules of logarithms and the rules of exponents.

... ln(ab) = ln(a) + ln(b)

... e^ln(a) = a

... (a^b)·(a^c) = a^(b+c)

_____

1) Use the second rule and take the antilog.

... e^ln(x) = x = e^(5.6 + ln(7.5))

... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents

... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms

... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)

2) Similar to the previous problem, except base-10 logs are involved.

... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.

... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5

... x ≈ 53,080.96

8 0
3 years ago
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