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dedylja [7]
3 years ago
14

There is a sidewalk of width x around a rectangular garden. If the garden measures twenty-feet by thirty-feet, then the combined

area of the garden and sidewalk is
Mathematics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

Area = 200 + 50 + x

Step-by-step explanation:

Given

Length = 20

Width = 30

Side Walk = x

Required

Determine the area.

To do this we need to get the new worth and length by adding the length of the sidewalk.

This gives:

Length = 20 + x.

Width = 30 + x

So, area becomes.

Area = (20 + x)(30 + x)

Area = 600 + 20x + 30x + x²

Area = 200 + 50 + x²

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Please helllpppp......​
MrRissso [65]

Answer:

y = 2x + 10

Step-by-step explanation:

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Find the value of 2x + 8y when x = - 5 and Y = 6​
mestny [16]

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Find the value of x. Round your answer to the nearest tenth
Sati [7]

x=13.8

<u><em>Step-by-step explanation:</em></u>

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2 years ago
3(s-5)/4 -3 = 4s- (s-3)/2<br>pls answer fast​
Jobisdone [24]

Answer:

s =  \frac{9± \sqrt{ - 39} }{4}

Step-by-step explanation:

\frac{3(s - 5)}{4 - 3}  =  \frac{4s \times (s - 3)}{2}

➡️ \frac{3(s - 5)}{1}  = 2s \times (s - 3)

➡️ 3s - 15 = 2 {s}^{2}  - 6s

➡️ 3s - 15  -  2 {s}^{2}  + 6s = 0

➡️ 9s - 15 - 2 {s}^{2}  = 0

➡️ - 2 {s}^{2}  + 9s - 15 = 0

➡️ 2 {s}^{2}  - 9s + 15 = 0

➡️ s =  \frac{ - ( - 9)± \sqrt{( - 9 {)}^{2}  - 4 \times 2 \times 15} }{2 \times 2}

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➡️ s =  \frac{9± \sqrt{ - 39} }{4}

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