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3 years ago

Simplify completely''''

Mathematics

1 answer:

34kurt3 years ago

8 0

Answer:

$\displaystyle \frac{2(x + 3)}{5x - 2}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Terms/Coefficients
Factoring

Step-by-step explanation:

<u>Step 1: Define</u>

$\displaystyle \frac{2x^2 + 16x + 30}{5x^2 + 13x - 6}$

<u>Step 2: Simplify</u>

[Fraction] Factor numerator: $\displaystyle \frac{2(x + 3)(x + 5)}{5x^2 + 13x - 6}$
[Fraction] Factor denominator: $\displaystyle \frac{2(x + 3)(x + 5)}{(x + 3)(5x - 2)}$
[Fraction] Divide: $\displaystyle \frac{2(x + 3)}{5x - 2}$

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3 years ago

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3 years ago

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2 years ago

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Please help me with these two questions

melisa1 [442]

Hi! It will be a pleasure to help you finding the solution to this problem, so let's solve each part:

<h2>PART 1.</h2><h3>Finding the correct expression.</h3><h3>Correct answer:</h3>

$\boxed{A. \ 1.50h+4}$

From the problem, we know the following data of the problem:

Laval parked at the beach.
Laval paid a fixed price of $4 for a pass.
Laval paid $1.50 for each hour.

Our goal is to find the the expression for the total cost for parking at the beach for h hours. So:

Step 1: Since we have a fixed price, this value will appear in our expression:

$4$

Step 2: Since Laval paid $1.50 for each hour, this can be represented as the following expression:

$1.50h$

Finally, we can write total cost (C) as the sum of these two expressions:

$C=1.50h+4$

Finally, our correct option is A:

$\boxed{1.50h+4}$

<h2>PART 2.</h2><h3>Finding h.</h3><h3>Correct answer:</h3>

5 hours

Here we have to find how many hours Laval spent at the beach knowing that he paid a total amount of $11.50. From the previous part, we know that our expression is:

$C=1.50h+4 \\ \\ For \ C=11.50 \\ \\ 11.50=1.50h+4 \\ \\ Subtracting \ 4 \ from \ both \ sides: \\ \\ 11.50-4=1.50h+4-4 \\ \\ 7.5=1.50h \\ \\ Dividing \ both \ sides \ by \ 1.50 \\ \\ h=\frac{7.5}{1.50}=5$