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Mashutka [201]
3 years ago
12

Zoey inflated 24 balloons for the high school dance. If Zoey inflated 15% of the total number of balloons at the dance, how many

balloons are there total?
Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

Total number of balloons= 160

Step-by-step explanation:

Giving the following information:

Number of balloons inflated by Zoey= 24

Proportion of balloons inflated= 15%

<u>To calculate the total number of balloons, we need to use the following formula:</u>

Total number of balloons = Number of balloons inflated by Zoey / Proportion of ballons inflated

Total number of balloons= 24 / 0.15

Total number of balloons= 160

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3 years ago
What is the length of the hypotenuse of the triangle when x=14
astra-53 [7]

The length of the hypotenuse will be equal to H=122.25 when value of x=14.

<h3>What is pythagorean theorem?</h3>

Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal the square of the sum of the other two sides.

It is given that:

Value of x=14

The perpendicular is  =6x+5=6x14+5=89

The base is  =6x=84

So by using the Pythagorean theorem:-

H^2=P^2+B^2\\\\\\H^2=89^2+84^2\\\\\\H=\sqrt{89^2+84^2}\\\\\

Hence the value of hypotenuse will be H=122.25

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8 0
2 years ago
A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
Ratling [72]

Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

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Answer

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Step-by-step explanation:

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What’s the value of Y?
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