Answer:
1: D
2: B
Step-by-step explanation:
Answer:
A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.
another way is
This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.
So,
(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA
Step-by-step explanation:
bran-list please
Answer:
y - 3 = 2/3(x + 2)
Step-by-step explanation:
slope = 2/3
point-slope form --> y - y1 = m(x - x1)
y - 3 = 2/3(x - -2)
y - 3 = 2/3(x + 2)
point slope form of the line is y - 3 = 2/3(x + 2)
Answer:
i think this might be right?
75p - ( p times -10) + 35 = w
Step-by-step explanation:
When we draw a circle with the centre at D and have a tangent HF to the circle D at point E, the angle DEF will be a right angle.
In other words angle DEF = 90 degrees
Since HF, the tangent, is a straight line, the other angle DEH should also be = 90 degrees because the straight line has an angle of 180 degrees
Therefore angle DEF = angle DEH = 90 degrees
Therefore, angle DEF is congruent to angle DEH (Option A)
