What is the slope of the line described 16x = 4y + 1
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Answer:
see the attached
Step-by-step explanation:
In the attachment, we will refer to the circles, bottom-to-top, as circles 1, 2 and 3. The black points of intersection, bottom-to-top, will be referred to by the letters A, B, C, D. The transversal line through the white point (W) and pink point (P) will be line q.
Step 1. Draw line q through point P so it intersects line m at some convenient point. Label that point W.
Step 2. Choose an arbitrary radius for your compass. Here, we have chosen it to be the length WB. It happens to be less than half the length of WP, but that is not a requirement.
Step 3. Draw an arc of the chosen radius centered at W and intersecting line q and line m. Label the intersection points A (on line m) and B (on line q). These intersection points are on circle 1.
Step 4. Draw an arc of the same radius centered at P. It should be a long enough arc that it would intersect the proposed line parallel to m. Label the intersection point on line q with label C. This intersection point is on circle 3.
Step 5. Adjust the compass width (radius) to the distance from A to B. This is the radius of circle 2.
Step 6. Draw an arc centered at C so that it intersects the arc of Step 4. This is circle 2, and you want it to intersect circle 3. Label that point of intersection D.
Step 7. Draw line PD parallel to m.
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The point of the construction is to create congruent alternate interior angles AWB and CPD, so that lines AW and PD are parallel.
