Answer:
Expectation=240
standard deviation=3.098
Step-by-step explanation:
This is a binomial probability function with n=250 and probability of success is 96%
-The expected value is calculated as:
Hence, the expected germination is 240 seeds
b. From a above, we have the value of p=0.96 and n=250.
The standard deviation of germination is therefore calculated using the formula:
Hence, the standard deviation of germination is 3.098
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
Answer:
The % of of acid in solution = 63.88 ml
Step-by-step explanation:
The solution of acid and water = 351 milliliters
The % of of acid in solution = 18.2% of 351 ml
Or, The % of of acid in solution = 
× 351 ml
Or, The % of of acid in solution = 63.882 ml
Hence ,The % of of acid in solution = 63.88 ml Answer
