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AnnyKZ [126]
2 years ago
14

Factor the expression 100n squared - 1

Mathematics
1 answer:
frez [133]2 years ago
4 0
Factor using the difference of squares.

a^2-b^2 = (a+b)(a-b)

100n^2-1
(10n+1)(10n-1)

Final answer: (10n+1)(10n-1)
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Answer:

\large\boxed{x=\dfrac{3\pi}{2}\ \vee\ x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}}

Step-by-step explanation:

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\sin x=-1\to x=-\dfrac{\pi}{2}+2k\pi,\ k\in\mathbb{Z}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}\\\\x\in[0,\ 2\pi)

x=-\dfrac{\pi}{2}\notin[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+2\pi=\dfrac{3\pi}{2}\in[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+4\pi=\dfrac{7\pi}{2}\notin[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}+2\pi=\dfrac{13\pi}{6}\notin[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}+2\pi=\dfrac{17\pi}{6}\notin[0,\ 2\pi)

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Your answer is b

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egoroff_w [7]

Answer:

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If AB = 8, and OX = 3 and is the perpendicular bisector of AB, which is the length of the diameter of this circle?
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By the Pythagorean theorem,

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<em>Comment on Pythagorean triples</em>

The triple of integers (3, 4, 5) is the smallest triple of integers that satisfies the relation of the Pythagorean theorem. The next smallest set is (5, 12, 13). These, and a few other similar triples such as (7, 24, 25) and (8, 15, 17) are often used in algebra and geometry problems because they make the numbers work out nicely. It is worthwhile to learn to recognize these.

7 0
2 years ago
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